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Ana Larrarte PHY 1001 Unit Two – Motion in 2 and 3 Dimensions Mathematical Assignment 1. Identify the vector and scalar quantities from the following list. {Temperature, weight, displacement, velocity, speed, time, mass, acceleration} Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction.
Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list. 2. A hiker walks along the city streets 4.0 km north, then 3.0 km west. What is the magnitude of the resulting displacement vector? Physics-Problem Solving Entries Key Idea The displacement vector is the straight-line distance between the initial and final positions of the hiker, regardless of the path taken. Stock of Data Distance walked north: 4.0 km •
Distance walked west: 3.0 km Solution
Distance walked north dn= 4.0km Distance walked west dw=3.0km Phygagorean theorem Magnitude displacement (4.0km)^2+(3.0)km^2 =16km^2=9km^2 =25km =5.0km Sanity Check The resulting displacement magnitude of 5.0 km 3 From the previous problem, what is the direction of the displacement vector in degrees from North? Round to 2 digits. Physics-Problem Solving Entries Key Idea Find the direction of the displacement vector in degrees from north (4.0 km) Stock of Data Use 0 = tan^-1 (Ay/ Ax)
Solution 0 = tan^-1 (3.0 km / 4.0 km) 0 = 36.87° north 4. Proceeding from landmark A, a vehicle moves along city streets 10 km north, then 14.2 km northeast, and finally 2 km south, and arrives at landmark B. What is the distance traveled, and the magnitude of the displacement between the two landmarks? Physics-Problem Solving Entries Key Idea Distance traveled and Displacement Stock of Data 10km north then 14.2 northeast 2 km south and back to landmark
Solution D=10+14.2+2=26.2km Displacement= 10-2+14.2 sin 45=18.04 Apply Pythagoras theorem x^2=(10.04)^2 + (18.04)
=426.2432 X= square root of 426.2432 = 20.64km Sanity Check The total distance traveled by vehicle is 26.2km The magnitude of the displacement between the 2 landmark is 20.64km 5. From the previous problem, what angle east of north does the displacement vector lie? Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction.
Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list.
6. Calculate the centripetal acceleration (in m/s
2
) of a car traveling 20 m/s around a curved road with a radius of 10 m. Physics-Problem Solving Entries Key Idea Centripetal acceleration is the acceleration experienced by an object moving in a circular path. Stock of Data
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Related Questions
vector A is -5m,30* north of east. what is the negative of vector A?
a. -5m,30* north of east
b. 5m,30* south of west
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d. -5m,30* south of west
These are quantities which are independent of one another.
a. derived quantities
b. physical quantities
c. accuracy
d. precision
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Remaining Time: 1 hour, 34 minutes, 39 seconds.
v Question Completion Status:
A Moving to another question will save this response.
Question 9
If the value of x-component of a vector is positive(+) and value of y-component is negative then the vector
will be in which quadirant?
O a. Vector will be in third quadrant.
O b. Vector will be in first quadrant.
O C. Vector will be in second quadrant.
d. Vector will be in 4th quadrant.
A Moving to another question will save this response.
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what is the main difference between distance and displacements. choose all that apply.
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4. Distance is a vector and displacement is a scalar
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Multiple Attempts This test allows multiple attempts.
Force Completion This test can be saved and resumed later.
Question Completion Status:
Moving to another question will save this response.
Question 1
An airplane undergoes the following displacements, all at the same altitude:
First, it flies 80.0 km in a direction 30.0° east of north. Next, it flies S7.0 km due south.
Finally, it flies 100 km 30.0° north of west.
Use components to determine how far the airplane ends up from its starting point.
76.2 km
77.8 km
80.9 km
74.7 km
O 79.3.0 km
A Moving to another question will save this response.
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5. Two vectors are defined below.
A = -3ỹ - 92
B = -6x + 5y
a) Find P, if P = AXB. Show all steps for full credit.
b) Explain why P-A and P-B equal zero.
c) Calculate P-A in component form to prove that it is equal to zero.
d) Explain how to determine the direction of P using your right-hand.
e) If |A| = 9.49, determine the angle between A and ŷ when placed
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Whats the main difference between distance and displacements. Choose all that apply.
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4. displacement is calculated by how far the object travels without paying attention to the direction of travel, and distance is calculated by the change in position it the object
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b) How far is Tanis from home at this point?
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Which of the following statements is correct?
a.) Time is a scalar quantity
b.) Velocity is a scalar quantity
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d.) Mass is a vector quantity
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(1) In which quadrant does the resultant vector lie?
First quadrant
Second quadrant
Third quadrant
O Fourth quadrant
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To estimate the height of a bridge over a river, a stone is dropped
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Displacement is which of the following types of quantities?
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B B) Scalar quantities can be added to vector quantities using rules of trigonometry.
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D D) Scalar quantities can be added to other scalar quantities using rules of ordinary addition
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Explain the difference between scalar and vector quantities. Exemplify your answer with:
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V. Solve the problem below by
finding the resultant vector using
a)graphical method with
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component method
A rural mail carrier leaves the post
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a direction 60 degrees south of east
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1) When representing a velocity vector,
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D. All of the above.
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a student begins her drive to school by traveling 14 miles in a direction of 45 degrees north of east. Next she travels 5 miles north. Finally, she travels 10 miles east when she arrives at school.
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1. ANALYTICAL METHOD OF ADDING VECTORS
Solve the same problem as PART 1 but this time analytically. START with the values
below. DO NOT USE VALUES FROM PART 1.
Suppose you walk 18.0 m straight west and then 25.0 m straight north. Let the positive x-axis
coincide with east and the positive y-axis be oriented in the northern direction.
(b) How far are you from your starting point? If you represent the two legs of the walk as
vector displacements A and B, then this problem asks you to find their sum R=A+B.
Enter to 3 significant figures
R=
m
(c) What is the direction (angle) of a line connecting your starting point to your final position
with respect to east (the positive x-axis)?
Enter to 3 significant figures
e=
degrees
Sense-making: Is there an upper bound or a maximum value the resultant can have? Is
your answer consistent with this upper bound?
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Solve the same problem as PART 1 but this time analytically. START with the values below. DO
NOT USE VALUES FROM PART 1.
Suppose you walk 18.0 m straight west and then 25.0 m straight north. Let the positive x-axis
coincide with east and the positive y-axis be oriented in the northern direction.
(b) How far are you from your starting point? If you represent the two legs of the walk as vector
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Enter to 3 significant figures
R=
m
(c) What is the direction (angle) of a line connecting your starting point to your final position with
respect to east (the positive x-axis)?
Enter to 3 significant figures
e=
✔degrees
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D = −6x − lý
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get the same results. Graph paper is not required,
you may sketch a square grid on your paper.
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b. B-C
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