preview

Stoichiometry Lab Report

Decent Essays

Stoichiometry and Determining the Limiting Reagent Abstract: Four chemical reactions will be done using different ratios of mixture between calcium chloride and sodium carbonate. The mixture of these two substances produces the precipitate calcium carbonate, which will be separated using filtration. After observing the tubes and collecting data, the limiting reagents were deduced from observing which amount of substance had the least amount of moles. It was found that in trials one through three, the limiting reagent was calcium chloride and in trial four, the limiting reagent was sodium carbonate. The actual yield in grams were compared to the theoretical yield in grams of product to provide percent yields of 63.89 %, 88.67 %, 89.6%, and …show more content…

The highest percent yield is seen in trial 3 whereas the lowest percent yield is seen in trial 4. Sample calculations:- Trial 1:- Moles of Na2CO3 = Molarity × Volume = (1.00 moles ×25.10 mL×1 liter)/(Litres×1000mL) = 0.00251 moles Moles of CaCl2 = Molarity × Volume = (0.0500 moles ×25.35 mL×1 liter)/(Litres×1000mL) = 0.00127 moles Theoretical yield grams = Moles of product × molecular weight of CaCO3 = 0.00127 moles × 100.089 g/moles = 0.127g Percent yield = (actual yeild (g))/(theoretical yeild(g))×100 = (0.0812g )/0.127×100 = 63.9 %

Get Access