1) Design a sequential circuit whose state table is shown below. Use JK flip-flops for the design.
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- Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).4 7) For the following sequential circuit: a) Tabulate the state table. b) Derive the state and output equations. c) Re-design the circuit using T flip-flops. Q1 Q -y K, K QP Jo Qo Q Ko K Q clock. please solve it as soon as possibleDesign a 2-bit counter using D-Flip flops with one input. When the input is 0, the ww m wwww w w m w i ww ww wwww www counter counts down, with the repeated sequence (11-10-01-00). When the input is 1, the counter counts repeated random sequence (00-01-11-10). a) Derive the state table for the sequential circuit. wwwww b) Derive the simplified flip flops input equations. www w w ww www m www ww c)Draw the logic circuit diagram of a 2-bit counter.
- 5. A sequential circuit has two flip-flops A and B, one input X, and one output Y. The state diagram is shown in the following figure. Design the circuit with D flip-flops using a 1-hot state assignment. 00/1 01/0 11/0 10/02. Sequential circuit shown below has two flip-flops A and B and one input x. It consists of a combinatorial logic connected to the flip-flops, as shown in Figure below. Analyze the circuit: a. Derive the next state and output equations. b. The state table of the circuit. c. Draw the state diagram. A K. 2-t0-1 MUX Y B' CLK23. The binary number 101110101111010 can be written in octal as a. 515628 b. 565778 c. 656278 d. 565728
- 2. Sequential circuit shown below has two flip-flops A and B and one input x. It consists of a combinatorial logic connected to the flip-flops, as shown in Figure below. Analyze the circuit: a. Derive the next state and output equations. b. The state table of the circuit. c. Draw the state diagram. A K B 2-t0-1 MUX B' K CLKQuestion: The flip-flops in the drawing below are positive edge triggered D flip-flops. Let Q2, Q1, QO = 0,0,0 initially. a) Plot the clock, Q2, Q1 and QO until the outputs begin to repeat. b) Show the circuits acts as a counter 00 1000 Hz/50%Design a sequential circuit with two flip-flops A and B, and one input x_in. When x_in = 0, the circuit goes through the state transitions from 00 to 10, to 01, to 11, back to 00, and repeats. When x_in = 1, the circuit will reverse the given sequence. a. Using D Flip-Flop. b. Using JK Flip-flop. Provide the state diagram, state table, state equations, and the circuit diagram.
- answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.You want to design a synchronous counter sequential (sequential) logic circuit. It will count from 0 to 9 and will not count the decimal digits in the last two digits of your student number. a. List the process steps that you will apply in the design approach. Create the State Chart and State Chart. b. Design the sequential circuit using JK Flip-Flop. Explain each step. Show that it has performed the desired action. last two numbers 02Rp 5. Complete the waveforms for the circuit of Figure 2. Cp Rp # Sp. K 0 D 6. Complete the waveform for Q for the flip-flop of Figure 3. Cp 0 0 14 0 310 3 Figure 2 Figure 3 D - Cp 1 Sp 7474 30-13 RD 9 RD J Q 5645 e Sp Sp Rp Rp Q Q