I need help with both parts of the question please . a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 Lat 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00atm pressure? V=0.78OLTI =20-1°c+ 273.15°7-293-2S%3DP= 1.00 atm%3Db) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume,pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was theinitial volume?

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1. a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 L at 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00 atm pressure? V= 0.78OL TI=20-1°c+ 273.15-293.2S T2=36.518 . P= 1.00 atm b) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was the initial volume?

1. a) A gas evolved during the fermentation of glucose (wine making) has a volume of 0.780 L at 20.1°C and 1.00 atm. What was the volume fermentation temperature of 36.5°C and 1.00 atm pressure? V= 0.78OL TI=20-1°c+ 273.15-293.2S T2=36.518 . P= 1.00 atm b) An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL, 0.60atm, and 45°C respectively. What was the initial volume?

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter10: Solutions

Section: Chapter Questions

Problem 89QAP

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