1. In the following circuit, what is the peak current, in amperes (A), through the secondary coil, iS? vA = 1 ∠ 0 V Z1 = -2.8j Ω Z2 = 9.5 Ω a = 7.1   (the answer is 0.01 but show how to get to this) (first picture goes with this problem

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