1. PROBLEM 1. A lot in the form of a convex polygon has the following technical description. The bearing of adjacent sides CD and DE are missing. LINE LENGTH BEARING N 32 deg 14 min E S 54 deg 17 min E АВ 525.36 BC 652.21 CD 418.24 DE 387.45 ? EA 569.52 N 37 deg 36 min W

1. PROBLEM 1. A lot in the form of a convex polygon has the following technical description. The bearing of adjacent sides CD and DE are missing. LINE LENGTH BEARING N 32 deg 14 min E S 54 deg 17 min E АВ 525.36 BC 652.21 CD 418.24 DE 387.45 ? EA 569.52 N 37 deg 36 min W

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 12.22. Water flows with a velocity of 3.0 m/s and a depth of 3.0 m in a rectangular channel. (a)…

A: Answer We are given Velocity of flow = 3 m/s Depth of channel = 3 m We can use Specific energy…

Q: 6. Discussion: 1. Is there a difference between the values of Qideal calculated by equation (1) and…

A: Note: Hi! Thank you for the question, As per the honour code, we are allowed to answer three…

Q: Solve 5,6

A: 5. The orientation of shallow knockout failure will always be in the direction of radial/axial…

Q: Q/ How many bricks you need to build a room and roof with interior dimensions of (5m x 4m). The…

A: Area of the roof = 5.48*4.48= 24.5504 m2. No of bricks required for roof = 58*24.5504= 1423.923=…

Q: A strip footing is needed to carry a load of 100 kN/m at a depth of 1 m. Shear strength parameters…

Q: B. Pump The oil tanks have a diameter of D = 12m. The initial depth of the oil in tank A is 20m, and…

Q: Find the bar force members LK, BC, IJ and ID using method of section

Q: reference you would like. Conditions for the 5 problems: First problem: Simply supported beam loaded…

A: As per bartleby guidelines here i am solving three question from top

Q: The shape factor of the section shown in figure is

Q: A car moves with initial velocity of 2 m/s and it is accelerating at rate of 4 m/s2. Find the final…

A: Given Initial velocity= 2 m/s Time = 2.5 sec

Q: A FLOCCULATION BASIN IS DESIGNED TO TREAT 20000 M3/DAY OF WATER WITH DETENTION TIME OF 150 MINUTES.…

Q: Calculate the force acting on ABC, BD, and 3 ft 6.5 ft DP 3 ft CDE. Draw B FBD 6.5 ft 6 ft E 5 ft

Q: The void ratios at the densest, loosest and the natural states of a sand deposit are 0.2, 0.6 and…

A: Maximum void ratio corresponds to soil in loosest state. Minimum void ratio corresponds to the soil…

Q: A FLOCCULATION BASIN IS DESIGNED TO TREAT 20000 M3/DAY OF WATER WITH DETENTION TIME OF 150 MINUTES.…

Q: 3- A region in which the sample undergoes permanent deformation without losing the ability to…

A: Questions: 3) A region in which the sample undergoes permanent deformation without losing the…

Q: PROBLEM 2. A compound curve passes thru a common tangent AB having a length of 300m. The radius of…

Q: A partially-saturated soil sample has natural moisture content of 25% and bulk unit weight of 18.5…

Q: W A CX

A: Given:- load W To find:- maximum bending moment at B and C

Q: 3) Suspended solids Small particles of organic or inorganic materials that settle down in,…

A: ASKED: To check the given statement if it is true or false. Given statement: Suspended solids…

Q: 1.7.4 Relationship between moisture content, bulk density, and CBR for crushed aggregate to be used…

Q: A 1600-lb in. couple is applied to a wooden beam, of rectang section 1.5 by 3.5 in., in a plane…

Q: Determine the maximum deflection for the beam shown in Fig. 2 using integration method. El is…

Q: Q.2 A, B, C and D are the activities of a network. Their normal and crash durations (in days) are…

Q: The cross-sectison of a simply supported plate girder is shown in figure. The loading on the grider…

Q: The axial load 396 kN applied to the lap joint is distributed equally among the three…

A: Answer We are given Axial load = 396 KN bolt diameter = 20.6 mm bolts width of plate w = 135.4 mm…

Q: A 300 mm diameter pipe carries water under a pressure (P,= 196.2 kPa.) with a Velocity of (V1= 3.5…

Q: "Al' rod in which loading as shown, determine total axial elongation for given loading condition.…

Q: 2.55 Two rods, identical except for their lengths, support the uniform rigid bar ABC of weight W.…

Q: If the weight of the box is W, find the normal reaction force (N) on the block shown below (mass of…

A: Given data Mass of the object =5kg

Q: Chapter 7- DOZER PRODUCTION A track-type dozer equipped with a power shift can push an average blade…

Q: Figure Q2 illustrates a compound curve that is to be set out at a highway intersection. Given that…

Q: A group of 9 piles, 12 m long and 400 mm in diameter is arranged in a square pattern in homogeneous…

Q: 8. Compute the AL and the Ad for each leg of the traverse shown below. Show the EL and the Ed as…

Q: Q6: Consider a 3 bedroom apartment with 3 roommates. The apartment has a volume of 11,742 m^3 with 3…

Q: Water at 4°C enters a tank of diameter DT = 50.5 cm at a constant mass flow rate of min= 1.1 kg/s.…

Q: A four-lane rural freeway segment has a 510 m grade length of 2% upgrade followed by a 630 m grade…

A: No of lane in both direction = 4

Q: The gear-pulling assembly shown consists of a crosshead CF, two grip arms ABC and FGH, two links BD…

Q: What is the beam deflection at point C when P = 10 kN, L = 1.5 m, E = 200 GPa, and I = 20E6 %3D %3D…

Q: • Flood Routing Monthly precipitatio runoff n (cm)(x) (cm)(Y) 6.9 Monthly • HW Month Jan-10 2.4 Q2//…

Q: ): In flow of sudden contraction, the change of pressure (Ap) is depends on the density p, the…

A: step 1-

Q: Given PI at 8+ 272.311, A = 24°24'20", and R = 500 m, compute E (external), M (midordinate), and the…

A: External Distance= E= RCos∆2-R= 500cos 12°12'10''-500= 11.558 m Midordinate = R1-cos∆2= 5001-cos…

Q: Deteminet verical dplacement of piCme dww e Ca m gures and incude the prriate unita Enter poe v the…

A: Determination of vertical deflection at C ###

Q: A steel portal frame has dimensions, plastic moment capacities and applied loads as shown in the…

Q: Steel frame (dead lo2 klf (Serua Wa and Wind live 24 Kif (Service) a kif= Ww 0ltimate H =10 ft 32 ft…

Q: For formation of collapse mechanism in the following figure, the minimum value of P, is cM,/L. M, &…

Q: XERCISES 1: Find the gradient of the function at the given point. f(x, y, z) = x2 + y? - 2z2 + z…

Q: create 3 simple flow chart on how cement, ceramic tile, and coca cola is manufactured.

Q: For the truss shown in Figure 2: (Take, A- 30 mm and E- 200 Gpa for all members) 1 Find the…

A: As per company's guidelines we can only answer first question. Kindly post other questions as…

Q: ) The, Conposite section Shown, is subjectuol to a Sagging bevding moment of loo kN,m, Deter mine…

Q: Why is iron added to concrete?

A: introduction- concrete- It is a paste that contains fine aggregates(sand), coarse aggregate(gravel),…

Concept explainers

Control Survey and Geodetic reductions

Control surveys or survey controls are used to establish reference points as a basis for various construction activities. Vertical and horizontal control points are to be established in a control survey to increase accuracy. After establishing the control points, all other types of surveys such as topographic, right-of-way, aerial mapping, construction layout, boundary surveys, and utility mapping can be worked upon so that control networks can be formed. The place from which the observations are made is called a survey station.

Question

a. What is the bearing of side DE?

b. What is the bearing of side CD?

1. PROBLEM 1.
A lot in the form of a convex polygon has the following technical description. The bearing of
adjacent sides CD and DE are missing.
LINE
LENGTH
BEARING
N 32 deg 14 min E
S 54 deg 17 min E
АВ
525.36
BC
652.21
CD
418.24
DE
387.45
?
EA
569.52
N 37 deg 36 min W

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The bearing of line AB is N 48* W, and the bearing of line AC is N 35*15 E. The angle BAC is: A. 167*15' B.83*15 C. 96*45 D. 12*45
Pt 2. 200 Zo0 200 300 300 300 y00 500 Find P4 F8 ASsume
Q2-) Fill the table according to given measurements. N BEARINGS AZIMUTHS 27"11 1 A1 A2 2 АЗ В A4 A5 SA 4A ЗА 2A 1A 3. 1391 37 50
N 250N 50mm 300 mm 300 mm b 200 mm 300 N 30 mm A V 450 N find Fx,Fy and moments at point a and b B 20 mm Section a - a s
1m 6m A 30° Water B Area of segment of = (1/2)r2[(n/180)0 – sine] a circle Gate ACB is in a shape of a sector of a circle whose radius is 6m as shown. Determine the following: a) Horizontal component FH is Blank 1 KN b) Vertical component Fv is Blank 2 KN C) Distance of FH from point "C" is Blank 3 m C) Distance of Fv from point "C" is Blank 4 m Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer Blank 4 Add your answer
C ... 1m 6m A 30° Water Area of segment of = (1/2)r²[(n/180)0 – sine] a circle %3D Gate ACB is in a shape of a sector of a circle whose radius is 6m as shown. Determine the following: a) Horizontal component FH is Blank 1 KN b) Vertical component Fv is Blank 2 KN c) Distance of FH from point "C" is Blank 3 m c) Distance of Fv from point "C" is Blank 4 m B.
F 20.555 -32.372 G A -30.960 A 53.696 9.641 D. -6.623 E.
구5 200 Sind moment Resultant about Point O 125
FIND CENTROID (C.G.) FIND Ix WI2X40 WIZX40 Ix= 307 im" A- 11.7 in 307 int WT 6X20 A-5.84m エx14.イm 1.09 im. WIZX40 とWTGX20 21 の
PC1 PI1 0+000 Lct PT1 R1 11 STATION NORTHINGS EASTINGS 0+000 11475.55 8927.24 PC2 9291.91 9546.66 PI1 11478.80 P12 11179.37 R2 V1 PI3 10804.76 9282.44 Lc2 PI4 10512.37 9433.48 13 12 PCC V1 11245.48 9490.41 PI2 V2 11074.50 9472.69 END 10203.85 9016.99 Lc3 R3 V2 LINE AZIMUTH DISTANCE 0-PI1 PI1-V1 V1-V2 PT2 V2-PI3 PI3-PI4 PI4-END PC3 R4 CURVE LC 1+140 PI3 1stCurve 2nd Curve 14 Lc4 3rd Curve 4th Curve 5th Curve PRC STATIONING 15 PC PT Lc5 PC2 P14 PCC R5 PT2 PC3 PRC PT3 PT3 END END OF ROAD ---- ----
200kg 12 wedge A 2865 N B) 2685 N 2391 N
12 x11 is not 144 i napplying equilibrium pls revise