100mA (b) 'If R₁-2002, R₁=1092, and RL-402, find IL . (Voltage controlled current source has A units.) Rf ww Sbstb (352 mnolomito + Pi202 normt snt pneu FK207 4 sulavne gle belts 9091 + Ti . 2013 negis ay eslenmen man houdad 2 to modowegia anibagomos sets bns esulavnom bri? (0. RL RI ay lif 19rito dos clienogodno IL = Now consider optimizing the value of RL, what resistance would you choose for maximum power delivered to R₁? What is the power dissipated on RL in this case? pera nas voivdur grad Sahtem songnggis 9) [b] RL (for max Power) = Pmax. with th

Delmar's Standard Textbook Of Electricity
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ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...
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100mA
(b)
' If Rf=202, R₁=102, and R₁=402, find IL . (Voltage controlled current source has A units.)
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finu ste yad
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pilot oino Jag of mot sitebr
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Now consider optimizing the value of RL, what resistance would you choose for maximum power
delivered to RL? What is the power dissipated on R₁ in this case?
Wing 1004 201
bnsox (6)
sibul
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IL
FH-
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RL (for max Power) =
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=
with
Transcribed Image Text:100mA (b) ' If Rf=202, R₁=102, and R₁=402, find IL . (Voltage controlled current source has A units.) Rf mnolen znolizoup ann suzum noto normit stignie V₁Z222 ΣΩ $352 3Ω 210 27absum V₁ Terobosnsaio 100y esilennon nart band ad 2 to mobovnegie gniboogaamos si bns esulavnéhe ant b finu ste yad + pilot oino Jag of mot sitebr svosioM inebrisqst se £ 10 S (1970anT Juo fabrbo meo adhism ahdamunya to zainegon ai tuods wor stulavsner (aj meg nt stor voy isiw no po26 s tim su 20 s b bre suisvaatie baitzib eved 2 xhism 2500 iL RL R₁ Sulu onli 2 to zodps marito dbes sohisen olvernmy to zelhago?q Now consider optimizing the value of RL, what resistance would you choose for maximum power delivered to RL? What is the power dissipated on R₁ in this case? Wing 1004 201 bnsox (6) sibul 3.xhtem 10:0903/a hutanc (b) IL FH- Im ns. RL (for max Power) = Pmax. = with
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