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11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon. CH₂OH H O OH H H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H OH H O 0 H OH H OH H O CH₂OH c) H, HO CH₂OH H OH H O H ОН H HO H H O Hemiacetal carbon. CH UM H OH H H D-glucose (cyclic form) OH CH₂OH R 0. H 0 OH H ОН OH H OH H H OH

11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon. CH₂OH H O OH H H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H OH H O 0 H OH H OH H O CH₂OH c) H, HO CH₂OH H OH H O H ОН H HO H H O Hemiacetal carbon. CH UM H OH H H D-glucose (cyclic form) OH CH₂OH R 0. H 0 OH H ОН OH H OH H H OH

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with number 24 because I struggle with my homework. I don't understand. Can you explain to me, please?

11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon- CH₂OH H O OH H L H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H 0. H H OH OH H OH H O CH₂OH c) H HO CH₂OH H OH H O H OH H HO O H H CH UM Hemiacetal carbon- H OH H D-glucose (cyclic form) R H CH₂OH + H OH H O -0. OH H OH OH H OH H H OH
Transcribed Image Text:11.24) The cyclic form of D-glucose (shown on right) is a cyclic hemiacetal. Recall that a hemíacetal is a molecule that contains both an OR group and an OH group that are bonded to the same carbon. Carbons that are bonded to both an OR group and an OH group are called hemiacetal carbons. Carbon number 1 in the cyclic form of D-glucose meets this criterium. The OH that is bonded to carbon number 1 is obvious, but the OR may not be immediately obvious to you. However, note that, beginning at carbon number 1 and moving counter-clockwise, as indicated by the red arrow in the structures shown on the right, the OR bonding pattern is seen. QUESTION: Which of the molecules shown below contain a hemiacetal carbon? a) Hemiacetal Carbon- CH₂OH H O OH H L H OH OH CH₂OH b) H HO CH₂OH H CH₂OH H OH H 0. H H OH OH H OH H O CH₂OH c) H HO CH₂OH H OH H O H OH H HO O H H CH UM Hemiacetal carbon- H OH H D-glucose (cyclic form) R H CH₂OH + H OH H O -0. OH H OH OH H OH H H OH
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