1294 grams of ice at -73.6 degrees Celsius is mixed with 362 grams of steam at 141 degrees Celsius. Assuming that at equilibrium the only phase remaining will be water, what will the final temperature of the water be? Specific heats: steam = 1.86 J/gC; water = 4.18 J/gC; ice = 2.09 J/gC; = 2259.1 J/g; = 333.8 J/g :

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1294 grams of ice at -73.6 degrees Celsius is
mixed with 362 grams of steam at 141
degrees Celsius. Assuming that at
equilibrium the only phase remaining will
be water, what will the final temperature of
the water be? Specific heats: steam = 1.86
J/gC; water = 4.18 J/gC; ice = 2.09 J/gC; =
2259.1 J/g; = 333.8 J/g
Transcribed Image Text:1294 grams of ice at -73.6 degrees Celsius is mixed with 362 grams of steam at 141 degrees Celsius. Assuming that at equilibrium the only phase remaining will be water, what will the final temperature of the water be? Specific heats: steam = 1.86 J/gC; water = 4.18 J/gC; ice = 2.09 J/gC; = 2259.1 J/g; = 333.8 J/g
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