13. (a) Compound C undergoes a reaction with SOC12 (or PC15) to yield compound D (Molecular Formula C10H10OCIBr) which has the following spectral data: Compound D: IR: 1685 cm; H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation. (b) Differentiate between the following: i) COSY and NOESY ii) COSY 90 and COSY 45

13. (a) Compound C undergoes a reaction with SOC12 (or PC15) to yield compound D (Molecular Formula C10H10OCIBr) which has the following spectral data: Compound D: IR: 1685 cm; H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation. (b) Differentiate between the following: i) COSY and NOESY ii) COSY 90 and COSY 45

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter24: Amines And Heterocycles

Section24.10: Spectroscopy Of Amines

Problem 25P

See similar textbooks

Similar questions

13. (a) Compound C undergoes a reaction with SOC1₂ (or PC15) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J=8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹3C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation. (b) Differentiate between the following: i) COSY and NOESY ii) COSY 90 and COSY 45
13. (a) Compound C undergoes a reaction with SOC12 (or PC15) to yield compound D (Molecular Formula C₁0H10OCIBr) which has the following spectral data: Compound D: IR: 1685 cm ¹; ¹H NMR: 87.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.
13. (a) Compound C undergoes a reaction with SOC12 (or PCls) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.
Identify the following compound from its IR and proton NMR spectra. C,H1,0: 'H NMR 8 3.31 (3H, s); 8 2.41 (1H, s); & 1.43 (6H, s) IR: 2110, 3300 cm-1 (sharp) Draw the compound.
Identify the following compound from its IR and proton NMR spectra. C,H1,0: 'H NMR 8 3.31 (3H, s); 8 2.41 (1H, s); & 1.43 (6H, s) IR: 2110, 3300 cm- (sharp)
Treatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppm
Propose a structure consistent with each set of data.a. Compound A:Molecular formula: C8H10OIR absorption at 3150–2850 cm–11H NMR data: 1.4 (triplet, 3 H), 3.95 (quartet, 2 H), and 6.8–7.3 (multiplet, 5 H) ppm b. Compound B:Molecular formula: C9H10O2IR absorption at 1669 cm–11H NMR data: 2.5 (singlet, 3 H), 3.8 (singlet, 3 H), 6.9 (doublet, 2 H), and 7.9 (doublet, 2 H) ppm
Compound X (molecular formula C10H12O) was treated with NH2NH2, -OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?
The compound that exhibits the following spectral data is IR: 1740 cm. 1H NMR: 6 0.9(t, 3H), 1.6(sext, 2H), 2.3(1,2H), 4.6(d, 2H), 5.2(d, 1H), 5.4(d, 1H), 5.9(m, 1H) ppm. El-MS(m/z): 71 (100%) O О
Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?
Reaction of aldehyde D with amino alcohol E in the presence of NaH forms F (molecular formula C11H15NO2). F absorbs at 1730 cm−1 in its IR spectrum. F also shows eight lines in its 13C NMR spectrum, and gives the following 1H NMR spectrum: 2.32 (singlet, 6 H), 3.05 (triplet, 2 H), 4.20 (triplet, 2 H), 6.97 (doublet, 2 H), 7.82 (doublet, 2 H), and 9.97 (singlet, 1 H) ppm. Propose a structure for F. We will learn about this reaction in Chapter 16.
An unknown compound A (molecular formula C7H14O) was treated withNaBH4 in CH3OH to form compound B (molecular formula C7H16O).Compound A has a strong absorption in its IR spectrum at 1716 cm−1.Compound B has a strong absorption in its IR spectrum at 3600−3200cm−1. The 1H NMR spectra of A and B are given. What are the structuresof A and B?