14 The brass bar shown is loaded axially in compression so that the maximum stress induced is 125 MPa. Calculate the total change in length (E = 100 GPa). 20 mm 70 mm + [=] 90 mm 30 mm
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- ools Fundamental of bio.. x 57 (73 of 286) e cdlaims compliance with the PDF/A standard and has been opened read-only to 4.13 Exercise Problems Problem 43 The uniform, horizontal beam shown in Fig. 4.51 is hinged to the wall at point A and supported by ar a cable attached to the beam at point C. Point C also th represents the center of gravity of the beam. At the other end, the cable is attached to the wall so that it makes an angle 0=68° with the horizontal. If the length of the beam is / = 4 m and the weight of the beam is W = 400 N, calculate the tension T in the cable and components of the reaction force on the beam at point A. Answers: T = 431 N, RAr = 162 N(→), RAy = 0 A Fie Fig. 4.51 Problem 4.3 Pr be 4.4 Using two different cable-pulley arrangements Problem7. A steel connecting rod is subjected to a completely reversed axial load of 160 kN. Suggest the suitable diameter of the rod using a factor of safety 2. The ultimate tensile strength of the material is 1100 MPa, and yield strength 930 MPa. Neglect column action and the effect of stress concentration. [Ans. 30.4 mm]Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du, DN4Du, DN5Du, DN6Du,DN7Du,…
- Vindow Help + 98% 4 Mon 9:56 A A docs.google.com F Sixth Amendment Video - Bill of Rights Lesso. G Earth and Space STAAR Review - Google S. G Nguyen - Physics STAAR Review - sics STAAR Review D @ Format Slide Arrange Tools Add-ons Help Last edit was 13 days ago O Present * Share IT 田 Background Layout- Theme Transition 1 2 TEL L 3 14 7 A diagram of the forces being applied to a box is provided (below). If the net force acting on the box is 10 N to the right, what is the magnitude of the force applied by the boy pulling to the left? Record your answer in the grid below. Show all work! Left Right 11 Newtons 8 Newtons 2. ? Newtons 21 Newtons Work/Math (2) (2 (2) (2) 40 40 40 Answer with units Click to add speaker notes )山TO@ MacBook Air 4) II F8 FIV F12 F10 000 F4 F9 F5 F6 F7A.) It is the boundary condition for fixed support Choices: Both choices Y=0 Y’=0 Either of the choices B.) It is a type of simple stress acting parallel to an area Choices: Flexural stress Shear stress Axial stress Bearing stress C.) For concentric row of bolts in a coupling connection, the shear deformations in the bolts is proportional to the: Choices Modulus of rigidity Diameter of bolt circle Radial distance Number of bolts note: please help us in the word meaing sample problems thank you1. 1100 A. 30% B. 1.1 m 1.0 m A F= 255 N 0.5 m 1.5 m DGB WARNING! The figure is not drawn to scale. For the force in the chain CB, ca IMAGES NOTES DISCUSS UNITS STATS HELP PREFERENCES Part Description the magnitude of component parallel to the hinge axis of the door, (include units with answer) 0.5 m Answer 118.77 N Format Check the magnitude of the component parallel to the edge of the door that 218.17 N is perpendicular to the hinge axis, (include units with answer) Format Check Save 25 pts.7 75% 5% try penalty 31.67 pts.95% 5% try penalty Status Tr ● W #tries: ** Tr • W. #tries:
- Topic: Calculation of stretch: small es. finite deformation Consider the mapping in 2-D only 21 = X1 +7X2 = X1+ u1 82 = (1+e)X2 = X2 + Uz. (1) 1. In terms of y and a compute F, i.e. the Fij's and then compute the Cj = FF.j; recall F = Fi. Now do the following. %3D 2. Take two fibers, viz. dX = e and dY = e2, that is two fibers of unit length along the ej and ez axes, respectively in the reference state. Compute the stretch of dX and dY. 3. Compute the small strains from this mapping with u = 7X2 and ur = eX¡ from above. What would these small strains suggest for the change in lengths of dX and dY? 4. Comment on what you found from the results of 2. and 3. You may want to sketch the deformed state to explain your comments.Q1: You are designing a high-pressure oxygen cylinder for hospitals fighting against COVID. The material used is layered unidirectional continuous fiber reinforced composite, as schematically shown in Fig.1 (a). In the 0° layer, the fiber is along the Y direction, and the fiber is along X direction in the 90° layer. The thickness of the 90° layer is 1.5 times of that of the 0° layer. The matrix material is an isotropic material with the Young's modulus E-10 GPa and volume fraction Vm-20%, while the continuous fiber is an anisotropic material with the Young's modulus E₁-250 GPa along the length direction, E2-20 GPa along the transverse direction and volume fraction V₁-80% a) Based on rule of mixture and mechanics of material method, calculate the effective Young's modulus along each direction (Ex, Ey, E₂). b) The as-produced (unloaded) inner radius Ro-0.1 m, the wall thickness H=0.005 m (<Stage Design A cable is used to support an actor as he swings onto the stage. Now suppose the tension in the cable is 920 N as the actor reaches the lowest point. What diameter should an 11-m-long steel cable have if we do not want it to stretch more than 0.50 cm under these conditions? R. Actor Sandbag SOLUTION Conceptualize Look back at the Example "A Grand Entrance," where we analyzed a cable used to support an actor as he swung onto the stage. We ignored any stretching of the cable there, but we wish to address this phenomenon in this example. Categorize We perform a simple calculation involving the equation F A Y = AL Li so we categorize this example as --Select--- v problem. Solve the Young's modulus equation for the cross-sectional area of the cable: FL; A = YAL Assuming the cross section is circular, find the diameter of the cable from d = 2r and A = ar (Use the following as necessary: F, Y, Li, AL, and r.): FL A d = 2r = 2 - = 2 Substitute numerical values. (Enter your answer…Problem 1: (50 points) In Avengers 2, Captain America's improved shield is made from unobtainium, a new material that will soon be available in a store near you. Unobtainium has the normal stress- strain diagram shown. The proportional limit, the elastic limit and the yield point are identical in this material. o [MPa] 2001 175 150 125 100 Fig.1 Normal stress-strain 75 50 25 0 0. 0.05 0.1 0.15 0.2 0.25 Unobtainium has a Poisson's ratio of 0.3. a. [6pts] Identify the yield point oy, the ultimate stress ou and the fracture stress of. Include units. c. [25pts] A bar of unobtainium has a length of 1.5 m, a width of 100mm and a height of 50 mm, as shown. The cross-sectional area is 50mm 100mm = 5 x 10-³m². The bar is subjected to an axial force of 375 kN. Find the normal stress in a cross-section of the bar. b. [5pts] How do you find Young's modulus from this graph? Find its value with units. whesta fins dus al hoss P = 375 KN 1.5 m 0.3 50 mm 100 mm & [mm/mm] Is the material within its…(Solid Mechanics) This finite element model is composed of 4 linear bar elements, each with a cross section of 10 mm² and material properties (E = 6 GPa, v=0.3). A weight of 200 N is applied and the nodes are named as shown below. (1) Compute the reaction forces. (2) What are the reaction forces when the weight is tripled to be 600 N? Find the solution without repeating the FEA. Explain why you can get the quick answer.Question 1: [Simple stresses] 1. A hydraulic system is used to apply a force in an external fixation device to hold broken ends. The piston of this hydraulic ram is 30 cm in diameter and the water pressure (shaded portion of the sketch) is 3 MN/m² as shown in Figure Q1.1. 3 MN/m? 30 cm 4 cm Figure QI.1 Hydraulic system Determine: 1.1. The stress in the piston rod which has dimeter of 4 cm 1.2. The elongation of the 2 m long piston rod. Take Young's modulus as E = 200 GN/m²SEE MORE QUESTIONS