Non-Standard Free EnergySolve the following problems. Show your solution.2. ΔG° is −32.7 kJ/mol of N2 for the reaction at 100°CN2(g)+3H2(g)⇌2NH3(g)Calculate ΔG for the same reaction under the following nonstandard conditions: In whichdirection must the reaction proceed to reach equilibrium?[N2]= 2.00 M,[H2]= 7.00 M,[NH3]= 0.021 M,and T = 100°C. AG° is -32.7 kJ/mol of N2 for the reaction at 100°C2.Ne(g)+3Hz(g)=2NH3(g)Calculate AG for the same reaction under the following nonstandard conditions: In whichdirection must the reaction proceed to reach equilibrium?[N2]= 2.00 M,[Ha] = 7.00 M,[NH3J = 0.021 M,and T = 100°C.

The reaction given is, => N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) Given: ΔGo at 100 oC = -32.7 KJ/mol =…

Answered: 2. AG° is -32.7 kJ/mol of N2 for the…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter16: Thermodynamics: Directionality Of Chemical Reactions

Section: Chapter Questions

Problem 119QRT

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Non-Standard Free Energy
Solve the following problems. Show your solution.

2. ΔG° is −32.7 kJ/mol of N₂for the reaction at 100°C
N₂(g)+3H₂(g)⇌2NH₃(g)

Calculate ΔG for the same reaction under the following nonstandard conditions: In which
direction must the reaction proceed to reach equilibrium?
[N₂]= 2.00 M,
[H₂]= 7.00 M,
[NH₃]= 0.021 M,
and T = 100°C.

AG° is -32.7 kJ/mol of N2 for the reaction at 100°C
2.
Ne(g)+3Hz(g)=2NH3(g)
Calculate AG for the same reaction under the following nonstandard conditions: In which
direction must the reaction proceed to reach equilibrium?
[N2]= 2.00 M,
[Ha] = 7.00 M,
[NH3J = 0.021 M,
and T = 100°C.

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