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2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. + SO2(g) PbO + C-Pb) + CO(g) AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 2H2+O2H₂O + H₂O - N₂O5 3.0), 1/2N2(g) + 3/202(g) +2H2(g) HNO3 AH = -174.1 kJ 2HNO₂ AH = -571.6 kJ AH = -73.7 kJ →

2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. + SO2(g) PbO + C-Pb) + CO(g) AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 2H2+O2H₂O + H₂O - N₂O5 3.0), 1/2N2(g) + 3/202(g) +2H2(g) HNO3 AH = -174.1 kJ 2HNO₂ AH = -571.6 kJ AH = -73.7 kJ →

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 45QAP: Use the appropriate tables to calculate H for (a) the reaction between copper(II) oxide and carbon...
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2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. PbO + C-Pb) + CO(g) AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. + SO2(g) 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 1/2N2(5) 2H2+O2H₂O + H₂O - N₂0 sig 2HNO 30) +3/2O2(g) + 2H2(g) → HNO3 AH = -174.1 kJ AH = -571.6 kJ AH = -73.7 kJ
Transcribed Image Text:2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. ΔΗ = .415.4 kJ PbS(+3/202) PbO () The oxide is then reduced to the metal with carbon. PbO + C-Pb) + CO(g) AH = +108.5 kJ Calculate 4H for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur dioxide and carbon monoxide. + SO2(g) 3. Calculate AH for the formation of one mole of N₂O, from the elements at 25°C using the following data. 1/2N2(5) 2H2+O2H₂O + H₂O - N₂0 sig 2HNO 30) +3/2O2(g) + 2H2(g) → HNO3 AH = -174.1 kJ AH = -571.6 kJ AH = -73.7 kJ
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