Prove that for all integers x, if x is not divisible by 7, then x^3 ≡ 1 mod 7 or x^3 ≡ −1 mod 7.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 92E
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1. Show, using modular arithmetic, that for all n ∈ N, 3(7^3n) + 2^n+3 is divisible by 11.


2. Prove that for all integers x,
if x is not divisible by 7, then x^3 ≡ 1 mod 7 or x^3 ≡ −1 mod 7.
Hint: There are 6 cases to consider.


3. Prove or disprove each of the following two statements.
(i) For all integers x and y and natural numbers n,
if xy ≡ 0 mod n, then x ≡ 0 mod n or y ≡ 0 mod n.


(ii) For all natural numbers n > 4 and integers x, if x^2 ≡ 4 mod n, then x ≡ 2 mod n.


4. Fermat’s Little Theorem says that for all natural numbers p and integers x, if p is prime then x^p ≡ x mod p.


(i) Show that the statement is wrong if we drop the assumption that p is prime.
[Remember: All you need to do is to give a counterexample.]


(ii) Show, by giving an example, that if p is not prime, then x^p ≡ x mod p can still be true for some integers x with x is not −1, 0, 1.

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Follow-up Question
●●●
2. Prove that for all a, b, m € Z \ {0} with gcd(a, b) = 1, ab|m iff a/m and b/m.
Before embarking on the proof, look at some examples, in order to understand what
this says, and to convince yourself that it indeed true, and that the assumption that
gcd(a, b) 1 is needed. This might also give you an idea for the proof. Also look at
some special cases, for example a = = 1.
=
"iff" stands for "if and only if". As above, this means that the proof should have two
parts, one for each direction. One direction is easy to prove, for the other direction
use Euclid's Lemma.
Transcribed Image Text:●●● 2. Prove that for all a, b, m € Z \ {0} with gcd(a, b) = 1, ab|m iff a/m and b/m. Before embarking on the proof, look at some examples, in order to understand what this says, and to convince yourself that it indeed true, and that the assumption that gcd(a, b) 1 is needed. This might also give you an idea for the proof. Also look at some special cases, for example a = = 1. = "iff" stands for "if and only if". As above, this means that the proof should have two parts, one for each direction. One direction is easy to prove, for the other direction use Euclid's Lemma.
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