2a₁b₁ Let A ab₂+ a₂b₁ ab3 + a3b₁ a₁b₂+ a₂b₁ 2a₂b2 a3b₂+ a₂b3 b3 +3₁ a2b3 + a3b₂. Expressing 2a3b3 A as the product of two determinants, show that A = 0. Hence, show that if ax + 2hxy + by² + 2gx + 2fy + c = (x + my + n) h b f (I'x + m'y + n'), then h g g f = 0.

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