2N₂Os (9) 4NO₂(g) + O₂(g) [NO₂0₂] N₂O₁ O Ke OK, O K. = NO, No, N₂O₂ NO₂0₁

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter17: Chemical Equilibrium
Section17.1: A State Of Dynamic Balance
Problem 3PP
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Question
For each of the following equilibria, write the
equilibrium constant expression for Ke
Y
Part A
2N₂Os (9) 4NO₂(g) + O₂(g)
O Ke =
O K₂=
O K.
OK-
Submit
Part B
[NO₂[0₂]
N₂O₁
Ke =
[NO₂¹0₂]
N₂0₂
N₂O₁]
NO₂0₁
N₂O,
NO₂] O₂
Request Answer
3F2(g) + Cl₂ (9) 2CIFs (9)
(CIF₂
CI, P
ICE,
P Pearson
Transcribed Image Text:For each of the following equilibria, write the equilibrium constant expression for Ke Y Part A 2N₂Os (9) 4NO₂(g) + O₂(g) O Ke = O K₂= O K. OK- Submit Part B [NO₂[0₂] N₂O₁ Ke = [NO₂¹0₂] N₂0₂ N₂O₁] NO₂0₁ N₂O, NO₂] O₂ Request Answer 3F2(g) + Cl₂ (9) 2CIFs (9) (CIF₂ CI, P ICE, P Pearson
Y
▼
Part B
3F2 (g) + Cl2 (g) = 2C1F3 (9)
[CIF 3]
[Cl₂][F2]
O Kc =
O Kc
O K
O Kc = [C1₂] [F₂13
[CIF3]2
Submit
-
Part C
[CIF3]2
[Cl₂] [2]
=
[C1₂] [F2]
[CIF 3]
Request Answer
Transcribed Image Text:Y ▼ Part B 3F2 (g) + Cl2 (g) = 2C1F3 (9) [CIF 3] [Cl₂][F2] O Kc = O Kc O K O Kc = [C1₂] [F₂13 [CIF3]2 Submit - Part C [CIF3]2 [Cl₂] [2] = [C1₂] [F2] [CIF 3] Request Answer
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