3) The circuit below shows resistors, inductors and capacitors, connected in series and in parallel. To demonstrate good understanding of RLC circuit theory in AC supplied circuits, you have been asked to solve the problem presented by the circuit shown in figure 1 below, by calculating the following: a) b) c) d) unduch =apach 2 The circuit impedance. The supply source current. The current through each component. The potential difference across each component. cercet curus. 2 = √√₁²² + x₁² ZJxã luss leads. 2. +90 - 90 30Vrms 50Hz 0° Vs ZI 2₂ 1 220 120mH 1002 R 330mH X₂ 150 tu ww 33μF = c = 27FL пес Ссг Zz 2 - 100T X330x10 Paralel

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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Questions A, B, C and D
3)
The circuit below shows resistors, inductors and capacitors, connected in series and in parallel. To
demonstrate good understanding of RLC circuit theory in AC supplied circuits, you have been asked to
solve the problem presented by the circuit shown in figure 1 below, by calculating the following:
a)
b)
d)
unduch
capach
The circuit impedance.
The supply source current.
The current through each component.
The potential difference across each component.
corect legs.
curus.
leads.
2 = √√₁²³² +*²²
Z₂ = √²-x₂².
2.
+96
- 90
30Vrms
50Hz
0°
Z₁ = Z₁ + Zz Zz
Vs
Z₁
Zz
22Q
120mH
Fig 1
1002 R
330mH3 X₂
15Q
X₁₁ = 27FL
d
33μF c
RLC
Ссг
167453
-3
- 100π X330x10
Parall
Transcribed Image Text:3) The circuit below shows resistors, inductors and capacitors, connected in series and in parallel. To demonstrate good understanding of RLC circuit theory in AC supplied circuits, you have been asked to solve the problem presented by the circuit shown in figure 1 below, by calculating the following: a) b) d) unduch capach The circuit impedance. The supply source current. The current through each component. The potential difference across each component. corect legs. curus. leads. 2 = √√₁²³² +*²² Z₂ = √²-x₂². 2. +96 - 90 30Vrms 50Hz 0° Z₁ = Z₁ + Zz Zz Vs Z₁ Zz 22Q 120mH Fig 1 1002 R 330mH3 X₂ 15Q X₁₁ = 27FL d 33μF c RLC Ссг 167453 -3 - 100π X330x10 Parall
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