3. Determine the probability that new baby Addams will have webbed feet(draw a Punnett square). The Addams Family Pedigree for Webbed Feet B=normal feet b-webbed feet Bb Bb bb 1 2 E --08- I Bb در Grandpa Addams 1 Cousin it 2 bb bb Grandma Addams 2 Bb 3 bb Mother Father Addams Addams 4 5 Fester bb 3 N Gomez Morticia Bb Bb bb BB or Bb Pugsley Wednesday 1 2 B. b BBB Bb bbbbb 25% chance of webbed fee because both Parents are heterozygo Bb, Bb ????? New Baby Addams 3 4. Does webbed feet appear to be a dominant or recessive trait? Explain your reasoning using examples from the pedigree. 5. Does webbed feet appear to be an autosomal (alleles are carried on non-sex chromosomes) or sex-linked (allele(s) is/are carried on a sex chromosomes, either X-linked or Y-linked) trait? Explain your reasoning using examples from the pedigree.
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- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
- n the space below, use colored pencils to create a pedigree with the following information. Follow the guidelines for a pedigree when creating this one. Ray and Elaine were married in 1970. They both had normal vision. They had 2 daughters and then a son. Both daughters, Alicia and Candace, had normal vision and never had any children of their own. The son, Mike, was colorblind. The son married Beth who also had normal vision and they had 2 children of their own, first Greg then Victoria. Victoria was colorblind, but Greg was not. Colorblindness is a sex-linked recessive trait. Do not forget what shapes are male and female. Place the names and genotypes of the people under their shape. Color your individuals the following: Red- for colorblindness White-for regular vision Blue- for individuals with regular vision but are carriers Green- unknown genotypePeter has 2 daughter both of them have straight her. He have 3 brothers and 2 sisters, two of his brother were died, while one of his sister was also died. Peter's wife have 2 brothers and 3 sisters. Peters younger daughter inherit the disease of her mother which is UTI Draw Peter's family pedigree here in III generation. Indicate the trait (physical trait (straight hair, wavy, curly) or an hereditary disease) that you have considered and provide a short description.PEDIGREE: Shaded individuals in the pedigree have a genetic disease. Individuals marrying into the family, that is individuals II–1, II–4 and II–6, have no history of the disease in their families.1. Determine the mode of inheritance ______________________________2. Give the genotypes of the following individuals
- Hi, I'm having trouble with my study guide for my upcoming genetics exam. If someone could please help with work shown and an explanation it would help so much! Thank you!! 2a. The pedigree below represents inheritance of rare condition. What pattern of inheritance is most consistent with the data? Assign alleles to all individuals to support your answer. If an allele is unknown, assign it a ? symbol. NOTE: Individuals whose phenotype or genotype cannot be determined are assumed to be unaffected and homozygous, unless otherwise indicated. 2b. In addition to the alleles you’ve indicated, describe 2 overall features of the pedigree that make it consistent with your chosen form of inheritance. 2c. Based on your mode of inheritance, what is the probability that the child of couple IV-4 x IV-5 will be affected? Show your work. attached is the pedigreeFill out the blanks of the pedigree (AA, Aa, or aa) How many children did the original couple have? How many grandchildren do they have?.Please indicate the recominant individiual in the given pedigree. Please explain your answer. AB CC BC AD AB CD AC CD AC DD AC BC AC BD AD CD BB вс BD
- The pedigree shows individual 1 and 2The following pedigree represent a disease that is very rare in the human population and completely penetrant. What is the mode of inheritance? What is the probability that a child indicated with an "A" will inherit the disease? SHOW YOUR WORK. A? Enr the toolhar prees Al T+F10 (PC)gr ALT+EN+F10 (Mar)Define the pedigree symbol(s) associated with each of the following individuals. Please be as specific as possible. Be sure to indicate WHOSE pedigree symbols you are defining. (i) II-1 and II-3 (ii) II-5 (iii) II-9-10 (iv) II-11 (v) IV-14 and IV-15 (vi) IV-18