4 ksi The state of plane stress at a point is shown on the element. (a) Draw Mohr's circle neatly to scale, and use it to complete part (b). (b) Determine the state of stress on an element rotated 35° counterclock- 20 ksi wise from the given element. Sketch the state of stress on the rotated element element. 9 ksi

4 ksi The state of plane stress at a point is shown on the element. (a) Draw Mohr's circle neatly to scale, and use it to complete part (b). (b) Determine the state of stress on an element rotated 35° counterclock- 20 ksi wise from the given element. Sketch the state of stress on the rotated element element. 9 ksi

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q-1) For the given state of stress, (a) draw Mohr's circle for this state of stress and show all values on it (b) determine the principal planes and the principal stresses, (c) determine the normal and shearing stresses after the element shown has been rotated through 25° clockwise, (d) determine the normal and shearing stresses after the element shown has been rotated through 10° counterclockwise. (e) Show the Gmax, min. Op, Os, Tmaxs o' values on an appropriate plane stress sketch. NOTE: The problem will be solved by only MOHR CIRCLE Method and all stresses and angles will be computed and indicated on Mohr Circle. All steps of solution will be displayed. Analytical solution will not be graded. 90 MPa + 30 MPa 60 MPa
The state of plane stress at a point with respect to the xy-axes is shown in Fig. (a). Using Mohr's circle, determine (1) the principal stresses and principal planes; (2) the maximum in-plane shear stress; and (3) the equivalent state of stress with respect to the x'y'-axes. Show all results on sketches of properly oriented elements. y20 MPa 50° 40 MPa 16 MPa (a)
The figure depicts the state of plane stress at a point. Sketch Mohr's circle 20,, o,, 02, and TMax for stress. Indicate on your drawing the following InPlane 13 ksi 2.5 ksi 25 ksi 25 ksi 13 ksi Determine the following: 01. O2. 0p. |TMaxl-
4 ksi The state of plane stress at a point is shown on the element. (a) Draw Mohr's circle neatly to scale, and use it to complete parts (b) and (c). 20 ksi (b) Determine the principal stresses, and sketch them on a prop- erly oriented element. 9 ksi (c) Determine the maximum in-plane shear stress and average normal stress, and sketch them on a properly oriented element. -20 -10 o (ksi) -30 -20 -10 10 20 30 10 20 T (ksi)
Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur. **The answer is tensile stress is 0 ksi at 90 degrees. **The answer is compressive stress is 7 ksi at 0 degrees. Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!
The state of stress at a point on an element of material is shown. Let sigmaX= 49.0 ksi, sigmaY= 17.0 ksi, and Txy= 11.0 ksi. Use this information to represent the principle state of stress and maximum in plane shear stress. Plot the mohr circle and state sigmaX' and sigmaY' and Tx'y' with unit. Also draw the state of stress on the rotated element.
The state of stress at a point in a soil beneath a level ground surface consists of a major principal stress of 70 kPa and a minor principal stress of 25 kPa. The major principal stress acts in the vertical direction. (a) Draw the Mohr's circle of stress and show the pole point (origin of planes). (b) Determine the maximum shear stress and calculate the orientation angle (relative to horizontal) of the plane of positive maximum shear stress. (c) Determine the normal stress and shear stress on a plane that makes an angle of -20° (i.e., 20° clockwise) relative to the horizontal plane.
Q1/ For the state of plane stress shown below, construct a Mohr's circle and determine:- (a) the principle stress acting at this point (b) the orientation of the principle stress (c) the maximum in-plane shear stress at the point and the corresponding average normal stress (d) the orientation of the maximum in-plane shear stress (e) show the results on elements 700 kPa pisres shear Stress at 100 kPa al stress aximum plar arenis ec 400 kPa
For the loading shown on the L-shaped part, determine the state of stress at points a, b, and c. Write each state of 12 in. stress in the form of a tensor, observing the r-y-z coor- dinate system shown, and sketch the stresses acting on a differential element at each point. 12 kip 1.8 in. 6 in. 12 kip 0. in. 1.0 in. 1.0 in.
The state of plane stress at a point is shown on an infinitesimal element below. Determine the stresses at the point on an element that is oriented 65° counter-clockwise from the x, y axes shown. Enter the shear stress on this rotated element Ta'y' (with correct magnitude and sign) in kPa correct to 3 significant digits below. 300 kPa y 400 kPa X 400 kPa 300 kPa
Knowing that the bracket AB has a uniform thickness of in and that P-5 kips, determine (a) the principal planes and principal stresses at point K and (b) the maximum sheanng stress at point K (Round the final answers to two decimal places. Input the answers with the appropriate sign) 25 im 2in (a) The principal stresses are Omax"41565 Oksi at Omin"13855 24 iksi at 24 (b) The maximum shearing stress is 2.771 Iksi.
To determine the normal and shear stresses on the indicated plane, we must first determine the orientation of the inclined plane relative to the x face of the stress element. Determine the magnitude of the counterclockwise angle between the x face and the inclined plane. Assume Sx = 170 MPa, Sy = 105 MPa, Sxy = 85 MPa, and ß = 65°. Sx Sxy В Sy Answer: 0 = 25 X O'