4. def find_value(tree: BinarySearchTree, n: int) -> int: find_value() function takes a binary search tree of integers and an integer value, n. Return the largest value in this tree that is less than n. Test case: tree: 2 5 7 1 4 6 11 9 n = 11, your function should return 9. (10 pts)
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- struct insert_into_bst { // Function takes a constant Book as a parameter, inserts that book indexed by // the book's ISBN into a binary search tree, and returns nothing. void operator()(const Book& book) { // // TO-DO (7) ||| ///// // Write the lines of code to insert the key (book's ISBN) and value // ("book") pair into "my_bst". END-TO-DO (7) | } std::map& my_bst; };int doo(node*root){ if(root !=0 ) { if(root->left==0 && root->right=D3D0) return root->data; int L=doo(root->left); int R=doo(root->right); if(L>R) return R; else return L;} } this code used for a. find the sum of leaves items in a binary tree b. the maximum item in the leaves of a binary tree c. find the minimum item in the leaves of a binary tree O d. find the minimum item in a binary treevoid F(node<int>&*root){if(root!=0){F(root->left); F(root->right); root->data=0; delete root;}root=0;} this code Select one: a. all of them b. Set all data items in the binary tree to 0 c. free the binary tree and returns it empty d. remove all items in the binary tree without changing its size
- void F(node<int>&*root){if(root!=0){F(root->left); F(root->right); root->data=0; delete root;}root=0;} this code Select one: a.all of them b.Set all data items in the binary tree to 0 c.free the binary tree and returns it empty d.remove all items in the binary tree without changing its sizeint doo(node*root){ if(root !=0 ) { if(root->left==0 && root->right==0) return root->data; return doo(root->right); } } this code used for O a. find the first right item in the binary tree if it has a right sub tree O b. find the maximum item in a binary tree if it has a right sub tree O c. find the number of right leaves in a binary tree if it has a right sub tree O d. find the maximum item in a binary search tree if it has a right sub treeJava Programming Language Create a class that accepts id numbers ranging from 1 to 29. The id numbers are nodes of a binary tree. Traverse the tree in inorder, preorder, and postorder and display the traversed values.
- /*LCA of Binary TreeSend FeedbackGiven a binary tree and data of two nodes, find 'LCA' (Lowest Common Ancestor) of the given two nodes in the binary tree.LCALCA of two nodes A and B is the lowest or deepest node which has both A and B as its descendants. Example: In this example, the green coloured node is the LCA to A and B.Alt TextNote:It is defined that each node is a descendant to itself, so, if there are two nodes X and Y and X has a direct connection from Y, then Y is the lowest common ancestor. Example:Alt TextNote: 1. If out of 2 nodes only one node is present, return that node. 2. If both are not present, return -1.Input format: The first line of input contains data of the nodes of the tree in level order form. The data of the nodes of the tree is separated by space. If any node does not have left or right child, take -1 in its place. Since -1 is used as an indication whether the left or right nodes exist, therefore, it will not be a part of the data of any node. The following…int doo(node*root){ if(root !=0) { if(root->left==0 && root->right=3D0) return root->data; int L=doo(root->left); int R=doo(root- >right); if(L>R) return R; else return L;}} This code used for? O a. Find the sum of leaves items in a binary tree Ob. The maximum item in the leaves of a binary tree Find the minimum item in the leaves of a binary tree O d. Find the minimum item in a binary treeint doo(node<int>*root){ if(root !=0 ) { if(root->left==0 && root->right==0) return root->data; return doo(root->right); } } this code used for a. find the maximum item in a binary search tree if it has a right sub tree b. find the number of right leaves in a binary tree if it has a right sub tree c. find the maximum item in a binary tree if it has a right sub tree d. find the first right item in the binary tree if it has a right sub tree
- Offline 3 Binary Search Tree Implementation Prepared by: Shoumik Saha 1. Find the given code of Binary Search Tree from our class. 2. Use it for the offline. Don't change anything that is already given, but you can add something (variable or function) if you need. 3. Implement these functions a. tree_successor b. tree_delete 4. You can check your code by experimenting with different values. Menu for successor and delete function is already added in the main function. *There will be a penalty for any late submission. **Any plagiarism will result in negative marking. ***TRY YOURSELF N.B.: 1. Follow the given slide for better understanding. 2. There willI be online on Binary Search Tree in the next lab class. ןןןןvoid F(node<int>&*root){if(root!=0){F(root->left); F(root->right); root->data=0; delete root;}root=0;} this code Select one: a. free the binary tree and returns it empty b. Set all data items in the binary tree to 0 c. remove all items in the binary tree without changing its size d. all of themGiven the following struct that represents a binary tree: struct Node { int key: Node "parent; Node "left; Node "right; Nodelint k) : key(k), parent(nullptr), left(nullptr), right(nullptr) (I: 1: Write a recursive function that prints out the nodes in a tree stored using the above structure in order to cout. The function prints the depth (root depth is at 0) and key of that node separated by a colon (Example "O: 10\n" for root with key 10). Your function CAN NOT create any local variables and can only use what is passed to the function. Use the below function signature (NOTE: this is not a class method). void inorderAndDepth(Node "node, int depth)