4. N₂ has a molecular weight of 28.0129 Daltons, a bit larger than that of a He atom (4.0017).(a) At a particular temperature, Ztrans = 2.80 x 1026 for He in a specific container. What is thetranslational partition function for a N₂ molecule in this container at the sametemperature?(b) At 100 K, the rotational partition function for N₂ is found to be 17.39. What would youexpect it to be at 225 K? LabelABсDEFGHJKLMNOPQRSTUVWXEquationEtotal= Eetec + Evib + Erot + EtransE₂ = hw (v + ²)Zvib =Evib =h²Erot= 27 J+1)=Bjj+1)Etrans (nx. ny. ₂) =3N-6[₁ hw; (v₁ + ²)3N-6(-1w(n)=-E-ENGE=N = n₁ZtransP₁ = gjeti/kgzταz=₁9₁e-B, or z=₁e-/kgh² (n.2B=8m L-Z=1 azz apZrotZrot =1kgT(9₁)",n₂!Zvib =■N!+A₁ e₁/ktgjet/katΣge-B(2mmk, T., 3/2h²Berot= ksz = Zelec Zvib Zrot ZtranskgTBaerib=a In Zaß√R T3, Ꮎ Ꮎ Ꮎe-Bho/21-e-BhuhokB2V+3N-6e-Bhoj/z=-ПIG-e-Bhay-Oyib./2T-e-vib/TZvibiP(b) = (1-e-b/T)e-/T

Answered: Image /qna-images/answer/591a6b51-ac71-4477-98c1-719da1f54fa1.jpg

4. N₂ has a molecular weight of 28.0129 Daltons, a bit larger than that of a He atom (4.0017). (a) At a particular temperature, Ztrans = 2.80 x 1026 for He in a specific container. What is the translational partition function for a N₂ molecule in this container at the same temperature? (b) At 100 K, the rotational partition function for N₂ is found to be 17.39. What would you expect it to be at 225 K?

4. N₂ has a molecular weight of 28.0129 Daltons, a bit larger than that of a He atom (4.0017). (a) At a particular temperature, Ztrans = 2.80 x 1026 for He in a specific container. What is the translational partition function for a N₂ molecule in this container at the same temperature? (b) At 100 K, the rotational partition function for N₂ is found to be 17.39. What would you expect it to be at 225 K?

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter18: More Statistical Thermodynamics

Section: Chapter Questions

Problem 18.32E

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