4. The figure below shows a beam clamped at both ends and the associated loading. Take E = 30x10° psi. Steel members (E,= 30×106 psi) 200 lb/in. 1.5 in. dia. 1.5 in dia. 2 in dia. 4 in 4 in 12 in c) Using FE formulation (based on FE element matrices via hand calculations), find the displacement and rotations at the two ends where the diameter changes from 1.5 to 2.0 inches.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter10: Statically Indeterminate Beams
Section: Chapter Questions
Problem 10.4.1P: A two-span, continuous wood girder (E = 1700 ksi) supports a roof patio structure (figure part a). A...
Question

Using FE formulation (based on FE element matrices via hand calculations), find the displacement and rotations at the two ends where the diameter changes from 1.5 to 2.0 inches. Provide full stiffness and global matrix.

4. The figure below shows a beam clamped at both ends and the associated loading.
Take E = 30x10° psi.
Steel members (E,= 30×106 psi)
200 lb/in.
1.5 in. dia.
1.5 in dia.
2 in dia.
4 in
4 in
12 in
c) Using FE formulation (based on FE element matrices via hand calculations), find the
displacement and rotations at the two ends where the diameter changes from 1.5 to 2.0
inches.
Transcribed Image Text:4. The figure below shows a beam clamped at both ends and the associated loading. Take E = 30x10° psi. Steel members (E,= 30×106 psi) 200 lb/in. 1.5 in. dia. 1.5 in dia. 2 in dia. 4 in 4 in 12 in c) Using FE formulation (based on FE element matrices via hand calculations), find the displacement and rotations at the two ends where the diameter changes from 1.5 to 2.0 inches.
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