5) Calculate the molar solubilities of CuS in pH = 1and pH = 4 containing H2S.Kccus=6,0x10 30[H+][HS¯]H2S→H*+HS°Ka1=5.7x10 8=[H2S][H*][S?-][HS¯]HSH*+s2-Ka2=1.2x1015=Ka1.Ka2=6.8X10-23_[H*]°[S²][H2S]H2S→2H*+s?-

Answered: Image /qna-images/answer/30933b5f-306d-4f29-bf90-e04af0e761d8.jpg

5) Calculate the molar solubilities of CuS in pH = 1 and pH = 4 containing H2S. Kccus=6,0x10 30 [H*][HS¯] [H2S] H2S+H*+HS° Ka1=5.7x10-8= [H*][S²-] [-SH] HS+H*+S?- Kaz=1.2x10-15= Ka1.Ka2=6.8×10-23_[H*]*[S²] [H2S] H2S+2H*+s?-

5) Calculate the molar solubilities of CuS in pH = 1 and pH = 4 containing H2S. Kccus=6,0x10 30 [H][HS¯] [H2S] H2S+H+HS° Ka1=5.7x10-8= [H][S²-] [-SH] HS+H+S?- Kaz=1.2x10-15= Ka1.Ka2=6.8×10-23_[H][S²] [H2S] H2S+2H*+s?-

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases

Section: Chapter Questions

Problem 110GQ

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

5) Calculate the molar solubilities of CuS in pH = 1
and pH = 4 containing H2S.
Kccus=6,0x10 30
[H+][HS¯]
H2S→H*+HS°
Ka1=5.7x10 8=
[H2S]
[H*][S?-]
[HS¯]
HSH*+s2-
Ka2=1.2x1015=
Ka1.Ka2=6.8X10-23_[H*]°[S²]
[H2S]
H2S→2H*+s?-

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