5. A 135g particle moves along the x axis according to the equation. =4.00-1.00 +3.00t2 -2.05t where in meters and this in seconds. Solve for the velocity and acceleration at t= 4 seconds.
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- 1. An ant travels 11.00 m [North], then 25.0 m [E 30.0 N] and finally 40.0 m [N70.0 W] to reach their nest. If the trip took 12.0 minutes, what was the ant's resultant displacement and average velocity?A particle moves in the x-y plane, starting from the origin with an initial velocity of ( 4i -8.7j) m/s. The particle experiences a constant acceleration of ( 4i ) m/s?. Calculate the speed of the particle at t = 5 s а. 99.69 b. 24.18 O' c. 584.70 d. 25.5345. A particle moves horizontally with velocity v, where v = (ri + 3j) ms', at time i seconds. Initially, r = (3i – 4j) m. The distance covered in 3 seconds is A 9v2 m B (12i + Sj) m C 13 m D (9i + 9j) m
- 7. At t = 0, a particle leaves the origin with avelocity of u 9.0m/s j the xy plane with an acceleration of a 2.0i- 4.0j m/s2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? A. 10 m/s B. 16 m/s C. 12 m/s D. 14 m/s E. 26 m/s maximum height above ch se, 2019. Departme15. A ball is hit upward with an initial velocity of 128 feet per second. After t seconds, its height h(t) is given by the function h(t) = -16t?+128t+4. What is the maximum height in feet of the ball? a. 268 feet b. 256 feet C. 264 feet d. 260 feetAt t = 0, a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0 i - 4.0 j) m/s 2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? O a. 14 m/s O b. 12 m/s O c. 16 m/s O d. 10 m/s O e. 26 m/s
- 49. Given these two velocities, C = (4î +2ĵ -2k̂) m/s and E= (5î -4ĵ +5k̂), find the magnitude of the velocity, v= 2C –E. a. 12.4 m/s b. 17.0 m/s c. 21.0 m/s d. 27.6 m/sV/A Spelunlier drops astone off of aclıff inadarl cave at the instmat he starts his stonwatch.Hehears the stone hit water 1.3secends utter he releases it. How fe below is the water? Give yor mswer in feed. A27.2 ft B 8.3 t7 ८घ दा cis.4 ft D)9.0 t# 3D. 2 ftThe speed of a particle moving along circle of radius r=4 m, is v(t) = 4t; where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s) of the particle at t = 1s is: a.4.0 b. 5.4 c. 8.9 d.2.1 e. 6.7
- 5. An object travels in zyz – plane experience an equation of motion given by a (t) = 8.10 i - 3.20 tj. a. Determine the average acceleration from t = 0.00s to t = 4.50 s b. Determine the velocity vector in terms of unit vector. c. Determine the instantaneous velocity when t = 3.00s. d. Determine the average velocity from t = 3.00 s tot – 5.60 s. e. Determine the velocity vector in terms of unit vector. f. Determine the exact position of the particle when t = 2.30 s.An object is dropped from rest from a high altitude and hit the ground later with a final speed of 114 m/s. Find the height (in units of m) from which the object was initially dropped. use g=9.8 m/s². Select one: O A. 1326 OB. 530 OC. 6498 OD. 58 OE. 663An object has an initial velocity v = 2.4i + 4.5j m/s. Over a period of time t = 2.9 s, its velocity becames v2 = 2.4i +35 m/s. The magnitude of the object's acceleration (in m/s?) is: a. 1.73 b. 0.52 c. 2.59 d. 3.07 e. 0.26