5. Thermodynamics Calculations. a. When ATP = 3.0 mM, ADP = 2.2 mM and P₁ = 12.1 mM, calculate AG at 298K. ATP (aq) + H₂O (1) ⇒ ADP (ag) + Pi (aq) K = 2.33 x 105 b. Under the conditions in part a., is the reaction spontaneous (no explanation needed)? c. Under the conditions in part a, will the reaction proceed to the left or right? Explain why be referencing the relationship between Q and K. d. Consider the following reaction in glycolysis: G-6-PF-6-P K = 1.97 Would you say this reaction is very spontaneous, fairly reversible, or very non-spontaneous? Please explain your reasoning. e. Using the same reaction in part d., calculate the equilibrium concentration of F-6-P if G-6-P = 0.100 M at equilibrium.

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Chapter18: Thermodynamics And Equilibrium
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Problem 18.111QP: Adenosine triphosphate, ATP, is used as a free-energy source by biological cells. (See the essay on...
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5.
Thermodynamics Calculations.
a. When ATP = 3.0 mM, ADP = 2.2 mM and P₁ = 12.1 mM, calculate AG at
298K.
ATP (aq) + H₂O (1) ⇒ ADP (aq) + Pi (ag)
=
b. Under the conditions in part a., is the reaction spontaneous (no
explanation needed)?
K = 2.33 x 105
c. Under the conditions in part a, will the reaction proceed to the left or right?
Explain why be referencing the relationship between Q and K.
d. Consider the following reaction in glycolysis:
K = 1.97
G-6-PF-6-P
Would you say this reaction is very spontaneous, fairly reversible, or very
non-spontaneous? Please explain your reasoning.
e. Using the same reaction in part d., calculate the equilibrium concentration
of F-6-P if G-6-P = 0.100 M at equilibrium.
Transcribed Image Text:5. Thermodynamics Calculations. a. When ATP = 3.0 mM, ADP = 2.2 mM and P₁ = 12.1 mM, calculate AG at 298K. ATP (aq) + H₂O (1) ⇒ ADP (aq) + Pi (ag) = b. Under the conditions in part a., is the reaction spontaneous (no explanation needed)? K = 2.33 x 105 c. Under the conditions in part a, will the reaction proceed to the left or right? Explain why be referencing the relationship between Q and K. d. Consider the following reaction in glycolysis: K = 1.97 G-6-PF-6-P Would you say this reaction is very spontaneous, fairly reversible, or very non-spontaneous? Please explain your reasoning. e. Using the same reaction in part d., calculate the equilibrium concentration of F-6-P if G-6-P = 0.100 M at equilibrium.
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