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- Lead poisoning has been a hazard for centuries. Some scholars believe that the decline of the Roman Empire can be traced, in part, to high levels of lead in water from containers and pipes, and from wine that was stored in leadglazed containers. If we presume that the typical Roman water supply was saturated with lead carbonate, PbCO3 (Ksp = 7.4 1014), how much lead will a Roman ingest in a year if he or she drinks 1 L/day from the container?3 Bal, (aq)+ 2 Nag POq Caq) 7 BalPO42 + l6 Nal laq • Consider the reaction of 30.0mL of 0.270M Balz with 20.0 mL of 0.3ISM Naz PO4. Lwhat quantity in meles of Balz are preset in the solution? are produced /What quantitg in moles of precipitate E ali Bal were consumed based on the balanced chomical equation? 6) What auantity in males of Na3 Pla aro present in soluction? d) What quantity in moles of precipitate are paduced if all the Naz PO, were cansumed based on the balanced chemi.cal equation? e) which reactant is limisting f What mass (in g) of precipitate is firemed when the limiting reactant is considered?A solution contains 1.01x102 M cobalt(II) nitrate and 1.43x102 M lead acetate. Solid potassium sulfide is added slowly to this mixture. What is the concentration of lead ion when cobalt(II) ion begins to precipitate? [Pb2t) -| M Submit Answer Retry Entire Group 5 more group attempts remaining
- K2CO3(aq) + 2HC2H3O2(aq) yields 2KC2H3O2(aq) + H2O(l) + CO2(g) How many moles of H2O can be obtained from 25.0 ml of 0.150 M HC2H3O2?A solution contains 6.73x103 M potassium hydroxide and 6.64x103 M potassium sulfide. Solid nickel(II) acetate is added slowly to this mixture. What is the concentration of sulfide ion when hydroxide ion begins to precipitate? [sulfide] = M Submit Answer Retry Entire Group 4 more group attempts remaining &5) 42.67 mL of 0.48 M NaOH was needed to titrate a 25.00 -mL ample of H,SOA. What is the concentration of the H,SO, solution? (show your work with units and conversion factures for problems # 1, 3, 4 and 5) hp
- A 2.663 g sample contain thiourea (NH,),CS (76.12 g/mol) was extracted into a dilute H,SO, solution and titrated with 37.88 mL of 0.006882 M Hg" according to the following reaction 4(NH2),CS+Hg [(NH),CS] Hg* Calculate the %((NH,),CS in the sample? 1. 02.981 % 2 07317 % 3. O98.45 % 4. 03.248 .Yttrium (III) carbonate (MM = 357.84 g/mol) has a Ksp of 1.0 x10-31. If 15.5 g Y2(CO3)3 is stirred into 2.16 L H2O, how many micrograms of yttrium (III) carbonate will dissolve?Report your answer to the nearest whole number.A chemist wishes to precipitate yttrium cations out of a 1.00 L solution. if the concentration of (in solution is 0.428 M and the K of yttrium iodate is 1.12 x 10, what mass of potassium lodate (00 must be added so that precipitation may begin? The molar mass of potassium lodate is 21A.00 g/mol. (27) (A) (B) (C) (D) 91.6g 64.0 ug (6.4 x 10* g) 411 mg 56.0 ng 137 mg (5.6 x 10* g) (E)
- 24. According to the solubility curve, which of the following ionic compounds would be considered unsaturated when 80 grams of solute is dissolved in 100 grams of water at 70°C? 150 140 130 120 110 100 NaNO3 90 870 60 NH C KCI NaCi 40 30 20 10 10 20 30 40 50 6070 80 90 100 Temperature (c) (A) NH.CI (B) KCI (C) Ce.(50.). (D) KNO: CONX NH3 Grams of soluteTo calculate the concentration of H2SO4 gravimetric analysis is done by the reaction given below. When the 5 ml of H2SO4 were mixed with BaCl2 (assume excess amount) the precipitation of BaSO4 occurs and the following data were obtained. What is the concentration of H2SO4? (BaSO4: 233.38 g/mol , H2SO4: 98.079 g/mol) H2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2HCI(aq) Mass of filter paper: 1.025 g Mass of filter paper + BaSO4: 1.200 g11. (ii) A student was given 400 cm of aqueous ammonia solution, NH,(ag), The student was asked to determine how many moles of NH, had been dissolved to prepare the solution. The student titrated 25.0cm of NH.(ag) and found that it reacted exactiy with 32.5cm3 of 0.100 mol dm sulturic acid. The equation for this reaction is shown below. 2NH,(aq) + H,SO,(aq) → (NH)SO,(aq) Calculate the amount, in moles, of NH, in the original 400 cm3 solution. mol answer =