6-Translate the following C program to MIPS assembly program (Please ex- plain each instruction in your code by a comment and submit a .asm file) #include using namespace std; int main int input[100], count, i, min; cout << "Enter Number of Elements in Array\n"; cin >> count; cout << "Enter // Read array elements for (i = 0; i < count; i++){ cin >> input[i]; } min - input[0]; // search num in inputArray from index to element Count-1 for (i = 0; i < count; i++){ if(input[i] < min){ min - input[i]; } count << "numbers \n"; } cout << "Minimum Element\n" << min; return 0;

6-Translate the following C program to MIPS assembly program (Please ex- plain each instruction in your code by a comment and submit a .asm file) #include using namespace std; int main int input[100], count, i, min; cout << "Enter Number of Elements in Array\n"; cin >> count; cout << "Enter // Read array elements for (i = 0; i < count; i++){ cin >> input[i]; } min - input[0]; // search num in inputArray from index to element Count-1 for (i = 0; i < count; i++){ if(input[i] < min){ min - input[i]; } count << "numbers \n"; } cout << "Minimum Element\n" << min; return 0;

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter9: Completing The Basics

Section9.3: The String Class

Problem 7E

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ill CS 2340- Live Lectures-20221025 X 2 of 2 UTD Fall 2022 CS 2340 Assignme X + File C:/Users/rubai/OneDrive/UTD%20Fall%202022%20CS%202340%20Assignment%203.pdf 53°F Cloudy #include using namespace std; 3-Translate the following program to MIPS assembly program (Please explain each instruction in your code by a comment and submit a .asm file) // Get the size m and n #define M 4 #define N 4 // Function to calculate sum // of elements in 2d array int sum(int arr[M] [N]) { int i, j; int sum = 0; // Finding the sum for (i = 0; i < M; ++i) { for (j = 0; j < N; ++j) { // Add the element sum sum + arr[i][j]; } return sum; } // Driver code int main() { int i, j; int arr[M] [N]; // Get the matrix elements int x = 1; for (i = 0; i < M; i++) for (j = 0; j < N; j++) arr[i][j] X++; // Get sum cout << sum(arr); return 0; (D Q T H {" 민 50 ENG 1 Во 12:12 AM 10/29/2022 X : +
Task using C language One common way of verifying if the data integrity of a file was preserved during a copy or transmission is to verify if the checksum matches. The checksum is a small piece of data computed from the original data. Your task is to compute a recursive function that maps an integer into a single digit to be used as checksum. Given an input integer in the range from 0 to 1012, the checksum is the sum of the digits of the input number. While the resulting sum has multiple digits, the checksum will be the sum of its digits instead. For instance: if the input is 34, the checksum is 7 (3+4); if the input is 99, the sum of its digits is 18 (9+9), so the checksum is 9 (1+8); if the input is 99999999999, the sum of its digits is 99 (9+9+9+9+9+9+9+9+9+9+9), whose sum of digits is 18 (9+9), so the checksum is 9 (1+8). Requirements Follow the format of the examples below. Make sure your variables and parameters have the correct data types. You must implement a recursive…
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ill UTD Fall 2022 CS 2340 Assignme X + 1 of 2 45°F Clear File C:/Users/rubai/OneDrive/UTD%20Fall%202022%20CS%202340%20Assignment%203.pdf #include int main() { |} 1-Translate the following program to MIPS assembly program (Please explain each instruction in your code by a comment and submit a .asm file) //Initialize array int arr[] int temp = 0; //Calculate length of array arr int length = sizeof(arr)/sizeof(arr[0]); {5, 2, 8, 7, 1}; //Displaying elements of original array printf("Elements of original array: \n"); for (int i = 0; i length; i++) { printf("%d ", arr[i]); } //Sort the array in ascending order for (int i = 0; i arr[j]) { temp = arr[i]; arr[i] arr[j] = temp; } } return 0; arr[j]; printf("\n"); //Displaying elements of array after sorting printf("Elements of array sorted in ascending order: \n"); for (int i 0; i < length; i++) { printf("%d ", arr[i]); (D Q Ø H P J ENG re 60 I Bo 60 N x : 6:57 AM 10/26/2022
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