6.7 The voltage across a 10-uF capacitor is shown in Fig. P6.7. Determine the waveform for the current in the capacitor. D(1) V 6 4- 2- 12 16 (ms) Figure P6.7

Find the Inductor current, the cap voltage, the Inductor energy, and the cap energy.

If the movement of 4.68 x 101+ electrons between the plates of a capacitor produces a 150-V change in capacitor voltage. find the capacitance.

The voltage with the following waveform is applied across a 5.00 micro Farad capacitor, what is the amount of total energy stored in the capacitor in the first 6 ms?.   PLease  help me .

. Find the value of R, if the energized inductor L spends 20 % of its energy in 10 msec after the switch is turned ON. to ImH R=?

Please draw the problem and answer, thank you.  A capacitor is made of 2 rectangular metal plates with side length of 3 cm x 6 cm separated by a distance of 2.36 cm with water in between the plates. The capacitor has a voltage of 110 v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?

A capacitor is made of 2 rectangular metal plates with side length of 3cmx6cm separated by a distance of 2.36cm with water in between the plates. The capacitor has a voltage of 110v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate? Follow this format- Given: Required: Equtions: Solution: Answer:

An uncharged 10 microF capacitor is charged by a constantcurrent of 1 mA. Find the voltage across the capacitorafter 4s.

The current through a 10-mH inductor is 10e-t/2 A. Find the voltage and the power at t = 5 s. The voltage is mv. The power is mW.

A capacitor is made of 2 rectangular metal plates with side length of 3cmx6cm separated by a distance of 2.36 with water in between the plates. The capacitor has a voltage of 110v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?