7) Assign partial charges on the CI-CI (polarized) below. This reaction proceeds through a three-membered ring halonium intermediate. The first step involves arrows similar to the carbene reaction above plus an additional arrow showing the Cl-Cl bond breaking. The second step is SN2 at the more substituted carbon. 8) Complete the following reaction by adding curved arrows, intermediates, and the expected products. S :CI-CI: :CI: 9) Label the Mechanistic steps above and the halonium ion intermediate. Because the second step is similar to SN2 the halides add anti to each other.

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter24: Carboxylic Acids & Derivatives
Section: Chapter Questions
Problem 12CTQ
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7) Assign partial charges on the Cl-Cl (polarized) below.
This reaction proceeds through a three-membered ring halonium intermediate. The first step involves arrows
similar to the carbene reaction above plus an additional arrow showing the Cl-Cl bond breaking. The second
step is SN2 at the more substituted carbon.
8) Complete the following reaction by adding curved arrows, intermediates, and the expected products.
St
r
:CI-CI:
:CI:
9) Label the Mechanistic steps above and the halonium ion intermediate.
Because the second step is similar to SN2 the halides add anti to each other.
Transcribed Image Text:7) Assign partial charges on the Cl-Cl (polarized) below. This reaction proceeds through a three-membered ring halonium intermediate. The first step involves arrows similar to the carbene reaction above plus an additional arrow showing the Cl-Cl bond breaking. The second step is SN2 at the more substituted carbon. 8) Complete the following reaction by adding curved arrows, intermediates, and the expected products. St r :CI-CI: :CI: 9) Label the Mechanistic steps above and the halonium ion intermediate. Because the second step is similar to SN2 the halides add anti to each other.
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