7. Find the AH of the reaction PCIS(g) - PCI:(g) + Cla(g) Given the following enthalpies of reaction Pa(s) + 6CI2(9) 4PCI:(g) 4PCI5(g) → Pa(s) + 10CI 2(g) AH = -2439 kJ AH = 3438 kJ

Chemistry: Matter and Change
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ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter15: Energy And Chemical Change
Section: Chapter Questions
Problem 78A: Alloys When a 58.8-g piece of hot alloy is placed in125 g of cold water in a calorimeter, the...
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STANDARD MOLAR ENTHALPHY OR FORMATION AND REACTION: Calculate the ∆H° of the following reaction. (Use 3 decimal places for the value of ∆H°f and express your answer as well in 3 decimal places.)
7. Find the AH of the reaction
PCI5(g) → PCI3(g) + Cl2(g)
Given the following enthalpies of reaction
P:(s) + 6CI2(g) → 4PCI3(g)
4PCI5(g) → Pa(s) + 10CI 2(g)
AH = -2439 kJ
AH = 3438 kJ
Transcribed Image Text:7. Find the AH of the reaction PCI5(g) → PCI3(g) + Cl2(g) Given the following enthalpies of reaction P:(s) + 6CI2(g) → 4PCI3(g) 4PCI5(g) → Pa(s) + 10CI 2(g) AH = -2439 kJ AH = 3438 kJ
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