7. In man, normal pigmentation is due to a dominant allele "A" and albinism to its recessive allele "a". A normal man marries an albino woman and their first child is an albino. What are the genotypes of these three people? Normal man Albino Woman Child An albino man marries a normally pigmented woman who had an albino mother. What are the possible genotypes and phenotypes of the children of this couple and the probability of each? 8. What are the genotypes of the parents? Genotypes Phenotypes

7. In man, normal pigmentation is due to a dominant allele "A" and albinism to its recessive allele "a". A normal man marries an albino woman and their first child is an albino. What are the genotypes of these three people? Normal man Albino Woman Child An albino man marries a normally pigmented woman who had an albino mother. What are the possible genotypes and phenotypes of the children of this couple and the probability of each? 8. What are the genotypes of the parents? Genotypes Phenotypes

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 7CT

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
FAlpQLSfiOhfAvlhxzCSiUll_6rt-nU5b0WI73UmWOxkOw8OCwk01ng/formResponse B 1 2 Bb x Bb b 4 The fur in both parents in this cross is * 1 B B Bb x Bb b 3 4 brown black O homozygous dominant homozygous recessive 3. 近
188IS Add-oIS al text BIUA E E E E Times New. 12 1 4. Purple fur (P) is DOMINANT in monsters. Yellow fur (p) is RECESSIVE. What is the genotype of a PURE PURPLE monster? = What is the GENOTYPE of a HETEROZYGOUS purple monster? What is the GENOTYPE of a YELLOW monster? Using the punnet square above, make a cross between TWO HETEROZYGOUS PURPLE MONSTERS. POSSIBLE OFFSPRING GENOTYPES PHENOTYPES edu gear El
In individuals affected by cystic fibrosis, salt crystals may appear afterperspiration dries up. In addition, the disease causes respiratory disorderswhich can be both debilitating and lethal. It occurs in individuals homozygousfor the recessive gene. Two normal parents had a daughter with thesymptoms of this disease, and a normal son who marries a normal womanwith an afflicted A test (salt concentration in perspiration of heterozygotes ishigher than normal) disclosed that both are indeed carriers of the gene. If thefirst child born to the mating in (b) was defective, what is the probability thatthe 2nd child would also be defective?Express answer in fraction form
Aav AaBbCc Normal No Spacing Heading 1 Paragraph Styles In man, two abnormal conditions, cataracts (C) in the eyes and excessive fragility (F) in the bones, seem to depend on separate dominant genes located on different chromosomes. Normal vision and normal bones are recessive traits. A man with cataracts and nomal bones, whose father had normal eyes, married a woman free from cataracts but with fragile bones. Her father had normal bones. 11. What is the genotype of the man with cataracts and nomal bones? What is the genotype of the woman with normal vision and fragile bones? What type of offspring might this couple expect? Genotypes Phenotypes What is the probability that their first child will, (a) be free from both abnormalities (b) have cataracts but not fragile bones (c) have fragile bones but not cataracts (d) have both cataracts and fragile bones? lili
Consider the following pedigree. 하 3 10 (5 3 2 (a) What pattern of transmission is most consistent with this pedigree? (1) autosomal recessive, (2) autosomal dominant, (3) X-linked recessive, (4) X-linked dominant. (b) If individual V-2 marries a normal individual, and if the condition has a pene-trance of 85 percent, what is the probability that their second child will express the trait? (c) On the third line, what does the diamond with a 10 in the middle mean?
Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation.  Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h .  Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________
AaBbCcDc AaBbCcD Ac Heading 1 Heading 2 Title Subtitle Subtle Em.. Emphasis Intense E... Strong Quote Int Paragraph Styles 4 Genetic Inheritance Patterns Retinitis pigmentosa (RP) can be autosomal recessive, autosomal dominant, or x-linked. Apparently the dominant forms are often less severe. Eric's form of RP is Usher's Syndrome, which is an autosomal recessive inheritance (i.e., you must get a copy of the defective carried on one of the chromosomes that determines sex. Usher's Type II is recessive, so for Eric this means that both his Mom and Dad are carriers of this condition. His brother, Dirk, does not have any symptoms of RP. gene from your Mom and one from your Dad). Autosomal means it is not Question below short answer approach image you are the genetics counselor, should Eric have children? Imagine he has a daughter (he has two, but both are adopted). What advice would you give Eric if his wife was a carrier from a genetics counseling viewpoint? Describe all the possibilities,…
In individuals affected by cystic fibrosis, salt crystals may appear afterperspiration dries up. In addition, the disease causes respiratory disorderswhich can be both debilitating and lethal. It occurs in individuals homozygousfor recessive gene. If 2 normal parents had a daughter with the symptoms ofthis disease, and a normal son, what is the probability that he might be acarrier of the recessive gene?Express answer in fraction form.
re ||| E 6. Label the genotypes for this pedigree of an X-linked recessive disorder (red- green colorblindness). (a) 2 2 3 1 3 a. How do you know? b. Label the genotypes. 4 O To 2 4 5 5 6 6 7. Is the following pedigree autosomal recessive, autosomal dominant or X-linked recessive? 2 8 O T 58
Classes SBI3C1-2 rr x rr Meet - rz pQLSeUir31BTTSeUl8EYpVNYpajrmzBg_g0n6oMivineMfM4k0w/viewform rr x Rr Classwork O Rrx Rr ORR X Rr Genet X SBI3C1-2 Genetics Two parents were known to be right-handed. Assuming that right-handed (R) is dominant to left-handed (r), what would be the genotypes of the parents if their son is left-handed? Google M Post Atte Sp * 1 poir