8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number
8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter15: Solubility And Complex Lon Equilibria
Section: Chapter Questions
Problem 47E: What mass of ZnS (Ksp = 2.5 1022) will dissolve in 300.0 mL of 0.050 M Zn(NO3)2? Ignore the basic...
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8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
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