A 1.00 L flask is filled with 0.106 moles of hydrogen iodide gas (HI) which then begins to decompose into gaseous hydrogen (H2) and lodine (12). At equilibrium, the concentration of HI is found to be 0.078 M. Calculate the equilibrium constant (Kc) for this reaction. 2HI(g)= H2(g) + 2(g) Express your answer using three decimal places.

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...
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A 1.00 L flask is filled with 0.106 moles of hydrogen iodide gas (HI) which then begins to
decompose into gaseous hydrogen (H2) and lodine (12). At equilibrium, the concentration of HI is
found to be 0.078 M. Calculate the equilibrium constant (Kc) for this reaction.
2HI(g)
H2(g)
+ 2(g)
Express your answer using three decimal places.
Transcribed Image Text:A 1.00 L flask is filled with 0.106 moles of hydrogen iodide gas (HI) which then begins to decompose into gaseous hydrogen (H2) and lodine (12). At equilibrium, the concentration of HI is found to be 0.078 M. Calculate the equilibrium constant (Kc) for this reaction. 2HI(g) H2(g) + 2(g) Express your answer using three decimal places.
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