A 125.3 gram sample of an unknown substance (MM = 189.50 g/mol) is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid = 1.62 J/g °C; heat capacity of gas = 1.04 J/g °C; AHvap = 78.11 kJ/mol; normal boiling point, Tb = 160.3 °C) %3D %3D How much energy (in kJ) is absorbed/released to cool the gas?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
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A 125.3 gram sample of an unknown substance (MM = 189.50 g/mol)
is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid = 1.62
Jlg °C; heat capacity of gas = 1.04 J/g °C; AHvap = 78.11 kJ/mol;
normal boiling point, Tb = 160.3 °C)
%3D
%3D
%3D
%3D
How much energy (in kJ) is absorbed/released to cool the gas?
Transcribed Image Text:A 125.3 gram sample of an unknown substance (MM = 189.50 g/mol) is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid = 1.62 Jlg °C; heat capacity of gas = 1.04 J/g °C; AHvap = 78.11 kJ/mol; normal boiling point, Tb = 160.3 °C) %3D %3D %3D %3D How much energy (in kJ) is absorbed/released to cool the gas?
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