A 2-kg block is suspended from a spring having a stiffness of 800 N/m. If the block is given an upward velocity of 4 m/s when it is displaced downward a distance of 150 mm from its equilibrium position, determine the equation which describes the motion. Assume that positive displacement is downward. x = 0.15sin(20t) + 0.2cos(20t) x = 0.1sin(20t) + 0.15cos(20t) 02cin(20+) 0.15coc(20+)
A 2-kg block is suspended from a spring having a stiffness of 800 N/m. If the block is given an upward velocity of 4 m/s when it is displaced downward a distance of 150 mm from its equilibrium position, determine the equation which describes the motion. Assume that positive displacement is downward. x = 0.15sin(20t) + 0.2cos(20t) x = 0.1sin(20t) + 0.15cos(20t) 02cin(20+) 0.15coc(20+)
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter15: Oscillations
Section: Chapter Questions
Problem 60AP: A mass is placed on a frictionless, horizontal table. A spring (k=100N/m) , which can be stretched...
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