A 3 phase, 10 kW, 400 V, connected induction 400 V, 4 pole, 50 Hz, star motor draws 20 A on full load. Its no load and blocked rotor test data are given below: No Load test: 400 V Blocked Rotor test: 90 V 6 A 15 A 1002 W 762 W Neglecting copper loss in no load test and core loss in Blocked Rotor test, estimate motor's full load efficiency.
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- Q2] Fill in the blank (9 Marks) 1-The current drwan by the armature of D.C. motor is directly proportional to 2- The speed of a D.C. shunt-wound motor will shunt field regulator is increased. 3- The synchronous speed of a three-phase induction motor is number of pairs of poles. Rotor copper losses Rotor input power in induction motor = 5- A 4-pole three-phase induction motor has a synchronous speed of 25 r.p.s. The frequency of the supply to the stator is_ Hz. 6- The power input to a mains transformer is 200VA. If the primary current is 2.5A, the secondary voltage is 2V and assuming no losses in the transformer, the turns ratio step down. is 7- A 200kVA transformer has an iron loss of 1 kW and full load cu loss of 2 kW. Its load kVA corresponding to maximum efficiency is kVA. 8- If cu loss of a transformer at 7/8th full load is 4900 W, then its full-load cu loss would be watt. 4- if the value of resistance of the proportional to the 9- The slight curvature at the lower end of the open…How rotor winding is derived the power in the three-phase induction motor? O a. from Single phase supply O b. from stator winding O c. None of the above O d. from slotsDesign and develop equivalent circuit model of a single phase Induction motor with th consideration of core losses present with the parameter consideration of stator resistance R1 and reactance X1 and two rotor parameters which includes r2,x2 and magnetising reactance xm. (Illustration is required) Draw by hand please
- Q2 ) A 220-V, 1.5-hp 50-Hz,wo-pole, capacitor-start induction motor has the following main-winding impedances: R1=1.40 2 X1=2.01 S Xm= 105 2 R2 = 1.50 2 X2=2.01 S2 At a slip of 0.05, the motor's rotational losses are 291 W. The rotational losses may be assumed constant. . Find the following quantities for this motor at 0.05 slip: (b) Stator Power factor (e)Pout (f) Tele (a) Stator current (d) PAG (c) Input Power (g) TL (h) Pconv (i) Efficiencytørque in new Draw the power flow diagram of induction motor and explain the different power losses, the air gap power and the converted pòwer. Explain how by solving the equivalent circuit of three phase induction motor the input current, input power factor, air gap power, rotor copper loss, converted power, output power and induced torque are calculated. (b)A 440 V, 50 Hz, 2-pole, Y-connected induction motor is rated 75 KW. The equivalent circuit parameters are: R, = 0.0752 R, = 0.0652 X = 1.22 Pare = 1.1kW X, = 0.172 X, = 0.17Q Pe =150W PEAW = 1.0kW For a slip of 0.04 find the line-eurrent, the stator"power factor, the stator copper_loss, the air gap power, the converted power the induced torque and the Toad torque. MISCAn 8 pole, 50 Hz slip ring induction motor runs at a slip of 2.67% on full load. The rotor resistance per phase of the winding is 0.2 ohm. What external resistance per phase must be added in the rotor circuit so that the motor now runs ate a slip of 17.33% such that the torque remains same in both the cases. (Ans: 1.1 ohm)
- A 110 V, 60 Hz, 6 – pole single phase induction motor 1/3 hp has the following equivalent circuit impedances: RI = 1.52 ohm, R2 = 3.13 ohm and x1 =2.10 ohm, x2 =1.56 ohm. Xm=58.2 ohm, The Friction, windage and stry losses =16W, the core loss = 35 W, For a slip of 0.05, calculation (a) input current, (b) power factor, (c) developed power, (d) output power, (e) speed (f) in put power (g) air gab power (h) T ind (i) T load 6) efficiency.Three Phase Induction Motor Question 1: A wound rotor induction motor runs with a slip of 0.05 when developing full load torque. Its rotor resistance is 0.45 0 per phase. If an external resistance of 0.50 per phase is connected across the slip rings, what is the slip for full torque?L-1). The 3-phase wound-rotor induction motor has .... . a) high starting torque b) low starting current c) both "a" and "b" d) neither "a" nor "b" L-2). The 3-phase wound-rotor induction.........a) motor has a wire wound rotor b) motor's rotor can be connected to an external resistive load by way of slip rings and brushes c) motor requires more maintenance than the 3-phase squirrel-cage induction motor d) all of the above L-3). The 3-phase wound-rotor induction motor's rotor circuit's resistance should be adjusted so it is__________ during starting. a) low b) high c) either "a" or "b" d) neither "a" nor "b" L-4). Will a 3-phase wound-rotor induction motor start with no external circuit connected to its rotor leads? a) yes b) no
- 6- Which of the following supply is given to the rotor winding of 3-Phase Induction Motor: a) DC Supply b) AC Supply c) No Supply d) Pulsating Supply 7- 3-Phase Induction Motor will have Starting Torque and Starting Current a) High, High b) Low, Low. c) High, Low d) Low, High 8- Which of the following method is used for controlling the speed of an induction motor: a) Changing number of stator poles b) Supply voltage control c) Frequency control d) All the options are correct 9- Which of the following method cannot be used for starting of 3-Phase Squirrel Induction Motor: a) Star-Delta Starting b) Line resistor startling c) transformer Starter d) Rotor Resistance Starting 10- The rotor of a stepper motor has no: a) windings b) commutator c) brushes d) all of the above(6) The air gap power of 440 V, 50 HZ 6 pole 3- phase induction motor is 100 KW. The rotor frequency is 1.3 HZ. Find rotor copper losses per phase.A 460-V (L-L), 25-hp, 60 Hz, four-pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: R1 = 0.6 ohms, X1 = 1 ohms, R2 = 0.3 ohms, X2 = 0.5 ohms, XM = 25 ohms. The total rotational losses are 1000 W and are assumed to be constant. Neglecting the core losses, for a rotor slip of 2 percent at the rated voltage and rated frequency. Find the motor's, (a) Stator current, (b) Power factor, leading or lagging? (c) Speed and Output Torque, (d) Efficiency, (e) The mechanical load of the motor changes and the new measurements show 35.7% increase in the current (I'=1.357xl) and 7.2% increase of the power factor (pf'=1.072xpf). For the new operating point find the motor's new speed (r/min).