A 44.4 mL sample of a 0.300 M solution of NaCN is titrated by 0.100 M HC1, K₁ for CN is 2.0 × 10-5. Calculate the pH of the solution: a. prior to the start of the titration pH b. after the addition of 93.2 mL of 0.100 M HCl PH = c. at the equivalence point pH d. after the addition of 173 mL of 0.100 M HCl pH =
A 44.4 mL sample of a 0.300 M solution of NaCN is titrated by 0.100 M HC1, K₁ for CN is 2.0 × 10-5. Calculate the pH of the solution: a. prior to the start of the titration pH b. after the addition of 93.2 mL of 0.100 M HCl PH = c. at the equivalence point pH d. after the addition of 173 mL of 0.100 M HCl pH =
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.144QP
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