A 780 N particle traveling at 10 m/s collides with a stationary 850 N particle.Immediately after the collision the 780 N particle has a speed of 8 m/s in a directionmaking an angle of 35° with the initial direction. Determine the velocity of the 850 Nparticle immediately after impact and the loss of kinetic energy as a result of thecollision.0235°01ANS.0₂ = 0;0₁ = 53.1°;V850 = 5.23 m/s;e=0.826Loss of KE = 234 Joules

Please see attached file for detailed solution.Explanation:

Answered: A 780 N particle traveling at 10 m/s…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

An object of mass m1 = 2.0 kg moving at 1.8 m/s collides with an object of mass m2 = 1.4 kg moving from the opposite direction with a speed of 1.5 m/s. After collision, m1 continues to go in the same direction with a speed of 0.3. What will be the speed of m2 after the collision? A 9.0 bullet traveling with a speed of 100 m/s gets embedded in a wooden block of mass 1 kg. The wooden block is hanging like a pendulum as shown in the figure below. To what height h will the wooden block rise, when it comes to a momentary stop. (Hint: do this as a two step problem, g = 9.8 m/s2).
A projectile is fired vertically from point A with an initial speed of 240 ft/sec. Relative to an observer located at B, at what times (find two times t₁ < t₂) will the line of sight to the projectile make an angle of 38° with the horizontal? Compute the magnitude of the speed of the projectile at each time, and ignore the effect of aerodynamic drag on the projectile. Answers: = B t2 = i i 38° 345' 240 ft/sec A sec, |v|= i sec, |v|= i ft/sec ft/sec
A concon is fired to a hill. The beginning of the hill is 200 meters away from the cannon and it is tilted by 25 degree from horizontal. The bullet's initial speed is 60.0 m/s. where does the bullet hits at the hill? * 5 60.0 m/s d =? 60° 25° 200 m
A bullet weighing 30 grams moving with a velocity of 100 m/sec hits a 5 kg bob of a simple pendulum horizontally. Determine the maximum angle through which the pendulurm string 0.5 m long may swing if The bullet get embedded in bob. M, =30 gm My= 5 kg ANS = deg (one decimal place)
Consider a bouncing ball. At time t = 0, the ball is dropped from a height_y(0) = họ, where ho is the initial height in meters. It falls freely. At some later time t₁ it hits the ground with a velocity y(t₁) < 0 m/s (meters per second). A bump event is produced when the ball hits the ground. The collision is inelastic (meaning that kinetic energy is lost), and the ball bounces back up with velocity −ay(t₁), where a is constant with 0 < a < 1. The ball will then rise to a certain height and fall back to the ground repeatedly. The behavior of the bouncing ball can be described by the hybrid system of Figure 1. There is only one mode, called free. When it is not in contact with the ground, we know that the ball follows the second-order differential equation, ÿ(t) = −g, where g 9.81 m/sec². = Bouncing Ball bump y(t) = 0/ bump y(t):= -ay(t) 5 free y(t) y(t)=-8 y(0) := hó y(0) := 0 Figure 1. Illustrate state variables y(t) and y(t), with initial conditions denote y(0) = ho and y (0) = 0.
For a perfectly elastic collision, u1+v1=u2+v2, or alternatively, u2−u1=v1−v2. If object 2 is initially at rest, then u2=0. Then v1−v2=−u1. However, for a partially elastic collision the relative velocity after the collision will have a smaller magnitude than the relative velocity before the collision. We can express this mathematically as v1−v2=−ru1, where r (a number less than one) is called the coefficient of restitution. For some kinds of bodies, the coefficient r is a constant, independent of v1 and v2. Show that in this case the final kinetic energy of the motion relative to the center of mass is less than the initial kinetic energy of this motion by a factor of r2. Furthermore, derive expressions for v1 and v2 in terms of u1 and r.
ENGS1202 Question 2 A. Figure 2 below shows a ball launched at an angle of 35° to the horizontal from the edge of a cliff of height 100 m. v= 20 m/s 100 m range Figure 2 Determine: i. the maximum height reached by the ball above its launch point. ii. the time taken for the ball to hit the ground. iii. the range of the ball as indicated in Figure 2. iv. the velocity on impact.
1.A 10 kg of 0.5 m radius wheel rotates at 360 rpm. What centripetal force ( KN ) is developed in the wheel? 2.A particle moves in such a way that a = 2 t + 2 m/s/s , where t is in seconds. Determine the velocity ( m/s ) of the particle after 5 seconds. 4.If a particle moves in such a way that a = 2 t - 1 m/s/s , where t is in seconds. Find the velocity ( m/s ) of the particle after 5 s .
6 A 100 kg particle moves with a velocity of (-2 m/s)i + (5 m/s)j. A 50 kg particle moves with a velocity of (1 m/s)i + (5 m/s)j. If the particles collide and stick together, what is velocity of the stuck-together particles post-collision? (1 m/s)i + (5 m/s)j (-1 m/s)i + (5 m/s)j (1 m/s)i + (1 m/s)j (-1 m/s)i + (-1 m/s)j
The trajectory of a soccer ball is analyzed when a goalkeeper decides to place it in the center of the field. Theball is kicked at a height of 1.20 meters measured from the ground with a direction of 25 degrees withrelative to the vertical. It was observed through cameras that the ball remained in the air for 2.4seconds. Determine:a- The speed with which the ball goes out.b- The hot horizontal distance it travels before hitting the ground.c- The maximum height the ball reaches.
Q1: In a volleyball match . if the player at point (A) hit the ball with an initial velocity of (13 m/s) and at an angle of (18) with the horizon. 1. indicate whether the ball will touch the net at (C) or not. 2. Find (b) [The distance between the net and the point of collision of the ball with ground]. 18+ 2.43 m 2 m 9 m
The pitcher throws the baseball with a release angle of 2 degree below horizontal, and speed of 47 m/s from a height of 1.8 m as shown in figure.(Figure 1) Figure h 18.5 m 2° 1 of 1 > 1.8 m Part A If the batter is 18.5 m away, determine the time for the ball to arrive at the batter. Express your answer with the appropriate units. t = Submit Part B ī Value Submit |μA P Pearson Provide Feedback Request Answer h=| Value Determine the height hat which it passes the batter. Express your answer with the appropriate units. μA Units Request Answer wwwww Units ? wwwwww F ? Next >

SEE MORE QUESTIONS

Recommended textbooks for you

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Control Systems Engineering

Mechanical Engineering

ISBN:

9781118170519

Author:

Norman S. Nise

Publisher:

WILEY

Mechanics of Materials (MindTap Course List)

Mechanical Engineering

ISBN:

9781337093347

Author:

Barry J. Goodno, James M. Gere

Publisher:

Cengage Learning

Engineering Mechanics: Statics

Mechanical Engineering

ISBN:

9781118807330

Author:

James L. Meriam, L. G. Kraige, J. N. Bolton

Publisher:

WILEY

SEE MORE TEXTBOOKS