A = [aij], 6 = [b.] %3D here aij = (-1)*+i(i – j), b; = (-1) for i = 1,..m and j = 1. Note that aij is the entry of A at the i-th row and the j-th column. Consider the following condition on vectors E R": (Condition1) A <5 & > .
A = [aij], 6 = [b.] %3D here aij = (-1)*+i(i – j), b; = (-1) for i = 1,..m and j = 1. Note that aij is the entry of A at the i-th row and the j-th column. Consider the following condition on vectors E R": (Condition1) A <5 & > .
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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!["onsdensiks Consider the m x n-matrix A and the vector be Rm that are given by
A = [aij],
6 = [bi]
where
aij = (–1)++i(i – j),
b; = (-1)' for i = 1,... m and j = 1,..· , n.
%3D
Note that aij is the entry of A at the i-th row and the j-th column.
Consider the following condition on vectors iE R":
(Condition1)
Aa < & > õ.
Write and run a python Jupyter notebook using the PULP package, to check whether there is
a vector iE R" that satisfies (Condition1),
• when m =n = 10,
and if it exists, find one.
Submit your screenshots or the pdf file of your Jupyter Notebook; it should show both the
codes and the results.
[For credits, you must write a python Jupyter notebook to solve this problem.]
Python Hint: Start with giving
М-10
N=10
You may want to use Python lists combined with 'forloop'. For example,
column=[j+1 for j in range(N)]
row=[i+1 for i in range(M)]
Then, one can define the matrix A and the vector 6, using Python dictionaries combined with
'forloop' as
a= {i:{j:(-1)**(i+j)*(i-j) for j in column} for i in row}
b = {i: (-1)**(i) for i in row}
In this way, the entry aij can be written in the later part of the Jupyter notebook code as
a[i] [i]. Similarly, b(i] for b;.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0a85d49e-8c8b-4552-a96b-b47a5fbf7366%2F700f19bf-13b7-4682-99b2-98a6d8115b54%2F90k2js_processed.jpeg&w=3840&q=75)
Transcribed Image Text:"onsdensiks Consider the m x n-matrix A and the vector be Rm that are given by
A = [aij],
6 = [bi]
where
aij = (–1)++i(i – j),
b; = (-1)' for i = 1,... m and j = 1,..· , n.
%3D
Note that aij is the entry of A at the i-th row and the j-th column.
Consider the following condition on vectors iE R":
(Condition1)
Aa < & > õ.
Write and run a python Jupyter notebook using the PULP package, to check whether there is
a vector iE R" that satisfies (Condition1),
• when m =n = 10,
and if it exists, find one.
Submit your screenshots or the pdf file of your Jupyter Notebook; it should show both the
codes and the results.
[For credits, you must write a python Jupyter notebook to solve this problem.]
Python Hint: Start with giving
М-10
N=10
You may want to use Python lists combined with 'forloop'. For example,
column=[j+1 for j in range(N)]
row=[i+1 for i in range(M)]
Then, one can define the matrix A and the vector 6, using Python dictionaries combined with
'forloop' as
a= {i:{j:(-1)**(i+j)*(i-j) for j in column} for i in row}
b = {i: (-1)**(i) for i in row}
In this way, the entry aij can be written in the later part of the Jupyter notebook code as
a[i] [i]. Similarly, b(i] for b;.
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