A balance has a sensitivty requirement of 4.0 mg. Explain how you would weigh 15 mg of a substance with an accuracy of ± 5% using lactose as the diluent.
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A balance has a sensitivty requirement of 4.0 mg. Explain how you would weigh 15 mg of a substance with an accuracy of ± 5% using lactose as the diluent.
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- Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray contrast agent that aids with the radiologic imaging of the anatomy. One such contrast agent is sodium diatrizoate, a nonvolatile water-soluble compound. A 0.378-m solution is prepared by dissolving 38.4 g sodium diatrizoate (NaDTZ) in.l.60 102 mL water at 3 1.2C (the density of water at 31.2C is 0.995 g/cm3). What is the molar mass of sodium diatrizoate? What is the vapor pressure of this solution if the vapor pressure of pure water at 31.2C is 34.1 torr?The torsion prescription balance has a sensitivity requirement of 4 mg. explain how you would weigh 5 mg of hydromorphone hydrochloride with an error not greater than 5%. Use lactose as the diluent.You are required to use commercially available Caffeine Tablet to obtain caffeine for your compounding. Each Caffeine Tablet weighs 500 mg and contains 150 mg caffeine and 350 mg of lactose. How many Caffeine Tablets would you crush in the mortar (to obtain the amount of caffeine you need) for compounding 10 capsules? How much lactose (from lactose bulk) would you use to compound 10 capsules? Acetaminophen 100 mgCaffeine 40 mg Lactose qs 320 mg
- Let me tell you about their task: The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels). The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). The students decided to save time and form five groups where each group was…A 1 mL sample of glycogen was calculated to contain 35 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCL. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 570 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence.A new method for glucose determination in serum (Method A) is to be compared to the established method (Method B). The table below shows the measured glucose concentration by each method for each patient. Is there a difference in the two methods at the 95% confidence interval? Patient1 Patient2 Patient3 Patient4 MethodA(mg/L) 1044 MethodB(mg/L) 1028 720 711 845 820 800 795 Patient5 957 935
- A 1 mL sample of glycogen was calculated to contain 21 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCl. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 340 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1 mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence. Show your working out such that the marker can easily understand it.…RMR (kcal/day) = (9.99 x 79.5kg) + (6.25 X 182.9cm) - (4.92 x 35) + (166 x 1)- 161w w w w w T Concentration (grams/kg H₂O) 1000 900 800 700 600 500 400 300 200 100 0 0 Solubility Curve for Potassium Dichromate (K₂Cr₂O₂) 10 20 30 40 50 60 70 80 90 100 Temperature (Celsius) Use the solubility curve for questions 22-25. You put 480 g K₂Cr₂O, in 1 kg of water? At which temperature will the 22. solution be saturated? A. 40 °C B. 70 °C C. 1000 °C D. Equal amounts of K₂Cr₂O; will dissolved at all of the listed temperatures. You put 150 g K₂Cr₂O7 in 1 kg of water? At which temperature will the 23. solution be saturated? A. 30 °C B. 50 °C C. 80 °C D. K₂Cr₂O, will dissolved equal fast at all of the listed temperatures.
- The protein concentration of a protein isolate was determined using the Bradford assay. Five dilution of bovine serum albumin (BSA) were prepared from a 5.00 mg/mL BSA stock solution. To these dilutions, 100 µl of Bradford reagent were added. After 5 minutes, the absorbance was taken at 595 nm. Standard # BSA, in mg/mL Volume of Bradford reagent, A595 in mL 1 5.0 0.000 1.00 5.0 0.134 3 2.00 5.0 0.265 4 3.00 5.0 0.388 4.00 5.0 0.497 The supernatant dilution was prepared by mixing 49 µL of the protein isolate with 16 µL water. The absorbance was taken 5 minutes after addition of 100 mL Bradford reagent. Calculate the protein concentration (in mg/mL) of the original isolate if the absorbance at 595 nm was 0.413. Note: Final answer format must be x.xxx (three decimal places). Round off only in the final answer. Do not round off in the middle of calculation.You are creating a standard curve for a protein experiment. You have to stock solution of BS a and would like to obtain dilutions. Explain how you would create a 1:1000 dilution of your protein stock solution.Draw a bar diagram on your sketch paper based on the table below and determine the non-carbon hardness (permanent hardness) in mg/L of CaCO3. Atomic weight Equivalent weight or molecular Concentration (mg/L) meq/L concentration (mg/meq) weight (g/mol) 100 Ca2+ 40 150 mg/L as CaCO3 150/50=3 (g/mol)/2(eq/mol)=50 Mg2+ 24 100 mg/L as CaCO3 100/50=2 Na* 23 46 mg/L K* 39 39 mg/L HCO3 61 225 mg/L as CaCO3 225/50=4.5 So,2 96 72 mg/L 35.5 71 mg/L O 25 mg/L of CaCO3 O 50 mg/L of CaCO3 O 100 mg/L of CaCO3 O 150 mg/L of CaCO3