A ball has coordinates x = t2 – 3t + 20 and y = 2 + 3t given in inches, wheret is in seconds. Find the magnitude of the velocity and acceleration of the ball when t = 3 s.
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- The vertical displacement (in m) of a plane is 1.5 t2 up; t is the time (in s) after takeoff. The plane releases a package 2.0 s after takeoff. What is the magnitude of the velocity (in m/s) when the packaged is released? Report your answer in the appropriate number of significant digits. Answer valueAjetliner, traveling northward, is landing with a speed of 68.2 m/s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 7.16 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive). Number i Units 4A particle moves along two dimensions based on the following position vector r= [2.0 m + (3.00 m/s)f ]i + [(3.0 m)t - (2.00 m/s2)rlj a. Find the distance it covered in the first minute. b. Find the general expression of the instantaneous acceleration of the particle.
- We are standing on the top of a 1040 feet tall building and launch a small object upward. The object's height, measured in feet, after t seconds is h(t) = 16t? + 128t + 1040. A) What is the object initial velocity? ft/second B) What is the highest point that the object reaches? feetNerve impulses in a human body travel at a speed of about 100 m/s. Suppose a person accidentally steps barefoot on a pebble. About how much time does it take the nerve impulse to travel from the foot to the brain (in s)? Assume the person is 2.00 m tall and the nerve impulse travels at uniform speed. s ?In 1991, four English teenagers built an electric car that has a velocity of 3 m/s [N 30⁰ E]. Suppose it takes 8.0 s for this car to accelerate to the new velocity of 18.0 m/s [W 30⁰ S]. What is the magnitude of the car’s acceleration?
- My question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.35. A person going for a walk follows the path shown in T Figure P3.35. The total trip consists of four straight-line paths. At the end of the walk, what is the person's resultant displacement measured from the starting point? Start 100 m 300 m End 200 m 30.0 150 m 60.0° Figure P3.35A rabbit runs across a parking lot. The path is such that components of rabbit's position with respect to an origin of co-ordinates as function of time are x = t2+ 10 and y = -9t+ 5. Here x, y are in meter and tin second. The magnitude of rabbit's displacement during first 5 seconds is
- The coordinates of a particle moving along a curve are x(t) = -2t2 +15 and y(t) = t2 -10t + 15 , m whent is in seconds. Calculate the magnitude of velocity and acceleration when t= 5 sec.A particle moves along the x-axis according to the equation x 2.00 + 3.00t - the acceleration of the particle. 1.00t2. where x is in meters and t is in seconds. At t=D3.00s, find5 Velocity of a particle changes from (3î + 4j) m/s to (Oi + 5j) m/s is 2 s. Find magnitude and direction of average acceleration.