A ball is projected at 72h-1 speed from the top of building. The building is 204 metres tall. The distance travelled in metres before it reaches the ground is as follows, s = u0t+1/2gt^2 where: u0= initial velocity (m. s-1) g = acceleration due to gravity (9.8m.s-2) t = time (s) Find the time for th ball to drop to a quarter (measured from the grour of the height of the building.

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
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A ball is projected at 72h-1 speed from the top of
building. The building is 204 metres tall. The
distance travelled in metres before it reaches the
ground is as follows, s = u0t+1/2gt^2 where: u0=
initial velocity (m. s-1) g = acceleration due to
gravity (9.8m.s-2) t = time (s) Find the time for th
ball to drop to a quarter (measured from the grour
of the height of the building.
Transcribed Image Text:A ball is projected at 72h-1 speed from the top of building. The building is 204 metres tall. The distance travelled in metres before it reaches the ground is as follows, s = u0t+1/2gt^2 where: u0= initial velocity (m. s-1) g = acceleration due to gravity (9.8m.s-2) t = time (s) Find the time for th ball to drop to a quarter (measured from the grour of the height of the building.
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