A battery with E= 4.30 V and no internal resistance supplies current to the circuit shown in the figure below. When the double-throw switch S is open as shown in the figure, the current in the battery is 1.00 mA. When the switch is closed in position a, the current in the battery is 1.18 mA. When the switch is closed in position b, the current in the battery is 2.02 mA. ww R₁ S R₂ ba 9b (a) Find the resistance R₁ KQ (b) Find the resistance R₂- kQ (c) Find the resistance R kQ ww R₂ O

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
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A battery with & = 4.30 V and no internal resistance supplies current to the circuit shown in the figure below. When the double-throw switch S is open as shown in the figure, the current in the battery is 1.00 mA. When the switch is closed in position a, the
current in the battery is 1.18 mA. When the switch is closed in position b, the current in the battery is 2.02 mA.
www
R₁ >R₂ R₂
(37
ba
(a) Find the resistance R₁.
KQ
(b) Find the resistance R₂.
(c) Find the resistance R3-
Ⓡ
Transcribed Image Text:A battery with & = 4.30 V and no internal resistance supplies current to the circuit shown in the figure below. When the double-throw switch S is open as shown in the figure, the current in the battery is 1.00 mA. When the switch is closed in position a, the current in the battery is 1.18 mA. When the switch is closed in position b, the current in the battery is 2.02 mA. www R₁ >R₂ R₂ (37 ba (a) Find the resistance R₁. KQ (b) Find the resistance R₂. (c) Find the resistance R3- Ⓡ
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