A body travels uniformly a distance of (13.8+0.2) m in a time (4.0 + 0.3) S. The velocity of the body within error limits is (a) (3.45+0.2)ms (b) (3.45+0.3)ms 1 (c) (3.45+0.4)ms (d) (3.45+0.5)ms -1
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- An object's position as a func of time is given by ; x(t) = - 200 (( t + 1 ) ^ - 1) + 6t^2. (Assume constants have proper SI Units) What are the object's instantaneous velocity at t = 3.00 seconds ? Answer = 48.5 m/sA car traveled at a rate of 50 km/hr for 8 minutes and then at 25 km/hr for 7 min and finally at 20 km/hr for 2 min. What is APPROXIMATELY the average speed for ?the complete trip of the car in (m/sec) 10.71 O 13.74 O non of them O 12.88 OA person takes a trip, driving with a constant speed of 96.5 km/h, except for a 20.0-min rest stop. The person's average speed is 67.0 km/h. (a) How much time is spent on the trip? 1.03 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. h (b) How far does the person travel? 67.23 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. km
- The velocity of a rocket is given as a function of time by v(t) = A(1 – e-bt) for 0 , t , 30 s, where the constants A = 150 and b = -0.15. [ d/dx (e-ax dx) = -a e-ax; ∫ e-ax dx = -1/a e-ax ] a) What are the SI units of A and b? b) What is the speed of the rocket at t = 10 s? c)Find the displacement of the rocket in the first 10 s ( from t = 0 s to t = 10 s)An object's position as a func of time is given by ; x(t) = - 200 (( t + 1 ) ^ - 1) + 6t^2. (Assume constants have proper SI Units) An object's instantaneous velocity at t = 3.00 seconds is 45.5 m/s What is the object's average velocity between t = 0 and t = 3.00 seconds? Answer is 68.0 m/s^2 What is the object's average acceleration between t = 0 and t = 3.00 s Answer : - 50.5 m/s^2A bolt is dropped from a bridge under construction, falling 82 m to the valley below the bridge. (a) How much time does it take to pass through the last 14% of its fall? What is its speed (b) when it begins that last 14% of its fall and (c) just before it reaches the ground? (a) Number i (b) Number 37.178 (c) Number 40.09 ! Unit Unit S m/s Unit m/s
- 2.68 0. CALC An object's velocity is measured to be v,(1) = a – Bt², . 4.00 m/s and B = 2.00 m/s. At t = 0 the object is at x = 0. (a) Calculate the object's position and acceleration as functions of time. (b) What is the object's maximum positive displacement from the origin? where a =the speed of a nerve impulse in the human body is baout 100m/s. if you accidentally stub your toe in the dark, estimate the time it takes the nerve impulse to travel to your brain. Please put full solutionThe acceleration of an object (in m/s2) is given by the function a(t)=7sin(t)a(t)=7sin(t). The initial velocity of the object is v(0)=−1v(0)=-1 m/s. Round your answers to four decimal places. v(t) = -7cos(t) + 6 The objects displacement from time 0 to 3 is: 17.01216 meters Find the total distance traveled by the object from time 0 to time 3.
- 9. A car traveled on a straight road, and it is found on the certain milestones (distance x) after a certain time (t) as follows t(InHrs): 0 1.42 1.82 0.48 0.78 1.10 100 150 * (InKms): 0 50 200 250 Compute the approximate time of maximum velocity. Ans. 0.552554An object's velocity as a function of time in one dimension is given by the expression; v(t) = 3.8t + 6.68 where are constants have proper SI Units. At what time is the object's velocity 61.2 m/s?A car is traveling at an unknown velocity. It accelerates constantly over 5.0s at a rate of 3.0(m)/(s^(2)) to reach a velocity of 30(m)/(s). What was the original velocity of the car?