(a) Calculate the strength and direction of the electric field, E, due to point charge of 2 nC at a distance 5.5 mm from the charge. For the direction, consider the line joining the point charge and point at the distance 5.5 mm. The direction on this line away from the charge is positive and the direction towards the charge is negative. E = 595.04 ✔ N/C (b) What force does the electric field found in the previous example exert on a point charge of -3.10-8 C? Hint: Indicate a force pointing in the direction of the field as positive and opposite the field as negative. -5 F= -1.785 x 10 ✔N ! No, that's not the correct answer.

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter23: Electric Forces
Section: Chapter Questions
Problem 29PQ: Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric...
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(a) Calculate the strength and direction of the electric field, E, due to point charge of 2 nC at a
distance 5.5 mm from the charge. For the direction, consider the line joining the point charge and
point at the distance 5.5 mm. The direction on this line away from the charge is positive and the
direction towards the charge is negative.
E = 595.04
✔ N/C
(b) What force does the electric field found in the previous example exert on a point charge of
-3.10-8 C?
Hint: Indicate a force pointing in the direction of the field as positive and opposite the field
as negative.
F=
-5
-1.785 X 10
N
No, that's not the correct answer.
Transcribed Image Text:(a) Calculate the strength and direction of the electric field, E, due to point charge of 2 nC at a distance 5.5 mm from the charge. For the direction, consider the line joining the point charge and point at the distance 5.5 mm. The direction on this line away from the charge is positive and the direction towards the charge is negative. E = 595.04 ✔ N/C (b) What force does the electric field found in the previous example exert on a point charge of -3.10-8 C? Hint: Indicate a force pointing in the direction of the field as positive and opposite the field as negative. F= -5 -1.785 X 10 N No, that's not the correct answer.
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