A capacitor of 10pfarad consist of two parallel plates each having an area of 200 cm^2, separated in air a distance d apart. This capacitor is charge to a potential difference of 250 volts and then disconnected from the source. Find the d, Q stored in the capacitor, Energy in joules and Energy needed to pull the plates to a distance of 2d.

A capacitor of 10pfarad consist of two parallel plates each having an area of 200 cm^2, separated in air a distance d apart. This capacitor is charge to a potential difference of 250 volts and then disconnected from the source. Find the d, Q stored in the capacitor, Energy in joules and Energy needed to pull the plates to a distance of 2d.

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...

See similar textbooks

Similar questions

In reference to the load, how are capacitors connected to help prevent voltage spikes and surges? Are capacitors connected in parallel or in series with the load?
(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = T 1 Air E1 83 Material A Material 3 Conductor Ans. C = 54 pF
The width of the plates of the capacitor in the figure is “a”. Bottom plate + Q = 480ε0 upper plate with Q = -480ε0 Accordingly: a) the capacitance of this capacitor b) the voltage between its ends c) polarization vector d) Find the polarized charge density on the surfaces e) Find the starting current and resistance before loading.
2) C. When the capacitor is fully charged, the top conductor while the bottom conductor D. Electric field lines are and a potential difference is E. The capacitance of a capacitor is defined as F. The unit of capacitance is
The plates of a parallel-plate capacitor are square and have the length of one side. 20 cm and the distance between the plates is 0.5 cm. The material between the plates is air.What is the capacitance of a parallel plate capacitor in farads?
.i. In a parallel plate capacitor, the cross sectional area of the plates are doubled and all other parameters remains the same. The ratio of Final capacitance to initial capacitance is found to be:
An air filled parallel plate capacitor is arranged such that the upper plate carries surface charge density 2C/m² and lower plate carries surface charge density -2C/m? as shown in figure. The electric field intensity over the top plate will be
Q14. An air filled parallel plate capacitor is arranged such that the upper plate carries surface charge density 2C/m2 and lower plate carries surface charge density -2C/m as shown in figure. The electric field intensity under the bottom plate will be -2a/ɛ0 -a,/ɛ0 None of these ロロ

Capacitors. Can you explain please why this is .50x10^(-13)?
Please derive this equation for capacitance at flat band:
What is a dielectric material, and what does it do? a. What are 3 ways capacitance can be increased by changing the materials?
Determine the total capacitance, total charge, individual voltage drop and charges across each capacitor. Use two decimal places for your answer. Put your answer for the individual voltage and charge for each capacitor in a table for faster checking. Thank you! Here are the values for the capacitors: C1 = 34 C6 = 29 C2 = 46 C7 = 38 C3 = 28 C8 = 23 C4 = 43 C9 = 32 C5 = 24 C10 = 23