A chemist titrates 80.0 mL of a 0.3825 M ethylamine (C2H5NH2) solution with 0.8602 M HBr solution at 25 °C. Calculate the pH at equivalence. The pK, of ethylamine is 3.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ×

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 55P
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A chemist titrates 80.0 mL of a 0.3825 M ethylamine (C2H5NH2) solution with 0.8602 M HBr solution at 25 °C. Calculate the pH at equivalence.
The pK, of ethylamine is 3.19.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.
pH = ☐
×
Transcribed Image Text:A chemist titrates 80.0 mL of a 0.3825 M ethylamine (C2H5NH2) solution with 0.8602 M HBr solution at 25 °C. Calculate the pH at equivalence. The pK, of ethylamine is 3.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ×
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