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A Chemistry student is asked to predict the pH of a potassium hydroxide solution when 1.82 g of potassium hydroxide is dissolved in 250 mL of water. He shows the steps of his calculations as follows: 1.82 g M56.11 g/mol Икон = 0.032 43...mol KOH 0.03243...mol CKOH == = 0.000 129 7...mol/L KOH 250 mL [KOH(aq)] = [OH(aq)] because it is a 1:1 ratio and 100% dissociation [OH (aq)] = 0.000 129 7...mol/L pH = -log[OH(aq)] = -log(0.000 129 7...mol/L) = 3.8869... pH = 3.897 Identify the three mistakes that the student made in his calculations. Correct the mistakes and provide the correct answer.

A Chemistry student is asked to predict the pH of a potassium hydroxide solution when 1.82 g of potassium hydroxide is dissolved in 250 mL of water. He shows the steps of his calculations as follows: 1.82 g M56.11 g/mol Икон = 0.032 43...mol KOH 0.03243...mol CKOH == = 0.000 129 7...mol/L KOH 250 mL [KOH(aq)] = [OH(aq)] because it is a 1:1 ratio and 100% dissociation [OH (aq)] = 0.000 129 7...mol/L pH = -log[OH(aq)] = -log(0.000 129 7...mol/L) = 3.8869... pH = 3.897 Identify the three mistakes that the student made in his calculations. Correct the mistakes and provide the correct answer.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.57QE: Two liters of a 1.5 M solution of sodium hydroxide are needed for a laboratory experiment. A stock...
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A Chemistry student is asked to predict the pH of a potassium hydroxide solution when 1.82 g of potassium hydroxide is dissolved in 250 mL of water. He shows the steps of his calculations as follows: 1.82 g M56.11 g/mol Икон = 0.032 43...mol KOH 0.03243...mol CKOH == = 0.000 129 7...mol/L KOH 250 mL [KOH(aq)] = [OH(aq)] because it is a 1:1 ratio and 100% dissociation [OH (aq)] = 0.000 129 7...mol/L pH = -log[OH (aq)] = -log(0.000 129 7...mol/L) = 3.8869... pH = 3.897 Identify the three mistakes that the student made in his calculations. Correct the mistakes and provide the correct answer.
Transcribed Image Text:A Chemistry student is asked to predict the pH of a potassium hydroxide solution when 1.82 g of potassium hydroxide is dissolved in 250 mL of water. He shows the steps of his calculations as follows: 1.82 g M56.11 g/mol Икон = 0.032 43...mol KOH 0.03243...mol CKOH == = 0.000 129 7...mol/L KOH 250 mL [KOH(aq)] = [OH(aq)] because it is a 1:1 ratio and 100% dissociation [OH (aq)] = 0.000 129 7...mol/L pH = -log[OH (aq)] = -log(0.000 129 7...mol/L) = 3.8869... pH = 3.897 Identify the three mistakes that the student made in his calculations. Correct the mistakes and provide the correct answer.
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