A compound with the molecular formula C13H1803 gave the following IR, C NMR, and HN C13H1003 100 4300 200 180 160 140 CD5-02-401 doublet 2H 9 HSP-43-267 triplet 2H triplet 1H 8 7 6 120 2008 There are eleven peaks on the spectrum. 5 WIVENBER T 100 80 ppm triplet 2H triplet 2H 4 ppm The the structure of the compound is: triplet 2H 60 3 1500 40 20 2 triplet 3H quintet 2H sextet 2H 1 0 0 1000

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Section13.SE: Something Extra
Problem 53GP: The compound whose 1H NMR spectrum is shown has the molecular formula C3H6Br2. Propose a structure.
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A compound with the molecular formula C13H1803 gave the following IR, 13C NMR, and ¹H NMR spectra:
C₁H00
LOD
4100
200
CDS-02-401
180 160 140
doublet 2H
9
HSP-43-267
triplet 2H
triplet 1H
8
6
2003
120 100
There are eleven peaks on the spectrum.
5
ppm
HAVENUMBER-
4
ppm
The the structure of the compound is:
triplet 2H triplet 2H
80
60
triplet 2H
1500
40
20
triplet 3H
quintet 2H
sextet 2H
1
0
0
1000
Transcribed Image Text:A compound with the molecular formula C13H1803 gave the following IR, 13C NMR, and ¹H NMR spectra: C₁H00 LOD 4100 200 CDS-02-401 180 160 140 doublet 2H 9 HSP-43-267 triplet 2H triplet 1H 8 6 2003 120 100 There are eleven peaks on the spectrum. 5 ppm HAVENUMBER- 4 ppm The the structure of the compound is: triplet 2H triplet 2H 80 60 triplet 2H 1500 40 20 triplet 3H quintet 2H sextet 2H 1 0 0 1000
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