A cup of coffee cools according to Newton's law of cooling (3) in Section 1.3. dT T-Tm - k(T - T) dt dt or (3) Use data from the graph of the temperature T(t) in the figure to estimate the constants T Te, and k in a model of the form of a first-order initial-value problem: dT/dt - k(T -T), T(0) = To: TA 200 150 100 50 25 50 75 100 minutes Tm To =

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A cup of coffee cools according to Newton's law of cooling (3) in Section 1.3.
dT
oT-Tm
dt
dT
= k(T - Tm)
or
(3)
dt
Use data from the graph of the temperature T(t) in the figure to estimate the constants T To, and k in a model of the form of a first-order initial-value problem: dT/dt = k(T - T), T(0) = To:
TA
200 -
150
100-
50-
0.
25
50
75
100
minutes
Tm =
To =
k
Transcribed Image Text:A cup of coffee cools according to Newton's law of cooling (3) in Section 1.3. dT oT-Tm dt dT = k(T - Tm) or (3) dt Use data from the graph of the temperature T(t) in the figure to estimate the constants T To, and k in a model of the form of a first-order initial-value problem: dT/dt = k(T - T), T(0) = To: TA 200 - 150 100- 50- 0. 25 50 75 100 minutes Tm = To = k
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